equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)
Perpendicular bisector lies at the midpoint of a line
Lets find mid point of (-9,-8) and (7,-4)
midpoint formula is


midpoint is (-1, -6)
Now find the slope of the given line
(-9,-8) and (7,-4)


Slope of perpendicular line is negative reciprocal of slope of given line
So slope of perpendicular line is -4
slope = -4 and midpoint is (-1,-6)
y - y1 = m(x-x1)
y - (-6) = -4(x-(-1))
y + 6 = -4(x+1)
y + 6 = -4x -4
Subtract 6 on both sides
y = -4x -4-6
y= -4x -10
equation for the perpendicular Bisector y = -4x - 10
F(x) = -4sin(2x + π) - 5
<u>Amplitude</u>
A = -π
<u>Period</u>
<u>2π</u> = <u>2π</u> = π
B 2
<u>Phase Shift</u>
<u>-C</u> = <u>-π</u> = ≈ 1.57<u>
</u> B 2<u>
</u>
Answer:
Yes
Step-by-step explanation:
Linear means a line, and x is not squared or anything in this equation. If you were to graph it, it would be a line.
By just changing the x and numbers you can solve it:
-4x=-8 => x=2