Answer:
3.55atm
Explanation:
We will apply Boyle's law formula in solving this problem.
P1V1 = P2V2
And with values given in the question
P1=initial pressure of gas = 1.75atm
V1=initial volume of gas =7.5L
P2=final pressure of gas inside new piston in atm
V2=final volume of gas = 3.7L
We need to find the final pressure
From the equation, P1V1 = P2V2,
We make P2 subject
P2 = (P1V1) / V2
P2 = (1.75×7.5)/3.7
P2=3.55atm
Therefore, the new pressure inside the piston is 3.55atm
First, assume the order of the given reaction is n, then the rate of reaction i.e. ![\frac{dx}{dt}=k\times[A]^{n}](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%7D%7Bdt%7D%3Dk%5Ctimes%5BA%5D%5E%7Bn%7D)
where, dx is change in concentration of A in small time interval dt and k is rate constant.
According to units of rate constant, the reaction is of second order.
(second order formula)
Put the values,

t= 587.9 s
Hence, time taken is 587.9 s
Answer:
t ≈ 235.47 secs
Explanation:
<u>Calculate how long it will take the transformation to go to 88% completion</u>
Given that Avrami equation ( <em>y </em>)= 1 - exp( - kt^n )
n = 2.3
t = 145 secs
reaction = 50% after t = 145 secs
Reaction = 88% after t = ?
attached below is a detailed solution
Formula of density is mass divided by volume.
Ga₂O₃ + 2NaOH + 3H₂O = 2Na[Ga(OH)₄]
[Ga(OH)]⁻ + 3e⁻ = Ga + 4OH⁻
n(Ga)=It/(zF)
I=0.200 A
t=40.0 min=2400 s
z=3
F=96485.33 Kl/mol
n(Ga)=0.200*2400/(3*96485.33)=0.00166 =1.66*10⁻³ mol