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liubo4ka [24]
3 years ago
5

If you move 50 meters in 10 seconds, what is your speed? Givens: d= t= Unknown: Formula: Plug in: Solve:

Chemistry
1 answer:
marta [7]3 years ago
6 0

Answer:

\huge\boxed{5 \ m/s}

Explanation:

<u>Given:</u>

Distance = S = 50 m

Time = t = 10 secs

<u>Unknown:</u>

Speed = v = ?

<u>Formula:</u>

v = S/t

<u>Plug In:</u>

S = 50 m , t = 10 secs

<u>Solution:</u>

v = 50 m / 10 secs

v = 5 m/s

Hope this helped!

<h2>~AnonymousHelper1807</h2>
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If this were a frictionless plane, what would be the ideal mechanical advantage?
slava [35]
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8 0
4 years ago
What would diluting the vinegar do to the rate of a reaction between vinegar and sodium hydroxide? decrease the rate of reaction
GarryVolchara [31]
Vinegar is aceti acid diluted in water.

The reaction of vinegar with sodium hydroxide is:

CH3COOH + NaOH ---> CH3COONa + H2O

That is an acid-base reaction.

The speed of reaction is proportional to the concentrations of the reactants.

Then, given thatn when you dilute the vinegar you decrease the concentration of CH3COOH, the rate of reaction will decrease.

Answer: decrease the rate of reaction.


4 0
3 years ago
A patient needs 0.024 g of a sulfa drug. There are 12-mg tablets in stock. How many tablets should be given?
emmainna [20.7K]
I would personally convert the 12 mg to g so I could see what I was working with. So 12 mg to grams is 0.012 g...

so 1 tablet is 0.012g. the patient needs 0.024 g. 

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hope this helps :)
7 0
3 years ago
Read 2 more answers
What is the mass of CO2 lost at 20 min from the limestone sample?
harkovskaia [24]

Answer:

The mass, CO2 and CO3 from the limestone sample is discussed below in details.

Explanation:

(A) mass loss of sample of limestone after 20 min

= 0.8437g-0.5979g = 0.2458 g

From the given reaction of limestone, 2 mol of the sample gives 2 moles of CO 2.

Therefore  

184.4 g ( molar mass of limestone) gives2× 44 g of carbon dioxide.

1 g of sample gives 88/184.4 g of carbon dioxide

Hence 0.2458 g sample gives

= 88/184.4 × 0.2458 g = 0.117 g carbon dioxide

(B) mole of CO 2 lost = weight/ molar mass

= 0.117 g / 44 g/mol =0.0027 mole

(C). 1 mol of limestone contain 2 mol of carbonate ion

From the reaction we know that carbonate ion of limestone is converted into carbondioxide

Hence lost carbonate ion = 0.2458 g

(D) we know that

1 mol limestone contain 1mol CaCO​​​ 3

Hence in sample present CaCO​​​ 3

= 1mole / 184.4 g × 0.8437 g= 0.00458 mol CaCO​​​3

8 0
3 years ago
Given the following equation: 2K + Cl2 -&gt; 2KCl How many grams of KCl is produced from 4.00 g of K and excess Cl2?
Thepotemich [5.8K]

Answer:

42.65g

Explanation:

Given parameters:

Mass of K = 4g

Unknown: Mass of KCl

Solution:

  Complete equation of the reaction:

              2K + Cl₂ → 2KCl

To solve this problem, we know that the reactant in short supply is potassium K and this dictates the amount of products that would be formed. The chlorine gas is in excess and we can't use it to determine the amount of product that would form.

Now, we work from the known to the unknown. Since we know the mass of K given in the reaction, we can simply find the molar relationship between the reacting potassium and the product. We simply convert the mass to mole and compare to the product. From there we can find the mass of KCl that would be produced.

Calculating number of moles of K

      Number of moles = \frac{mass}{molar mass}

        Number of moles of K =  \frac{4}{39} = 0.103mol

From the given reaction equation:

   2 moles of K will produce 2 moles of KCl

 Therefore 0.103mol of K will produce 0.103mol of KCl

To find the mass of KCl produced,

   Mass of KCl = number of moles of KCl x molar mass

Molar mass of KCl = 39 + 35.5 = 74.5gmol⁻¹

Mass of KCl = 0.103 x 74.5 = 42.65g

4 0
3 years ago
Read 2 more answers
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