All categories

3 years ago

Write the electronic configuration of 6c element and state the group,period to which it belongs

Chemistry

1 answer:

Alexus [3.1K]3 years ago

7 0

Answer:

Carbon = 1s2 2s2 2p2 group= 14 period = 2

Explanation:

group can be taken from the electronic configuration here it is 2s2 2p2 so it should belongs to 4A or 14

You might be interested in

Fill in the coefficients that will balance the following reaction:

andrey2020 [161]

Answer:

CH4 + 2 O2 → CO2 + 2 H2O

Explanation:

There are one mole of O2 on the left side and on the right side there are three moles of O2. And to fix it you would need to make it two moles of O2 to have four molecules of O2 on the left side. Then you would make two moles of H2O to have a total of four moles of O2 on the right. Therefore, CH4 + 2 O2 → CO2 + 2 H2O is the answer.

7 0

3 years ago

Read 2 more answers

Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t

Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

$(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)$

Now we have to calculate the amount of heat released or absorbed in both processes.

For process 1 :

$Q_1=m\times \Delta H_{fusion}$

where,

$Q_1$ = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

$\Delta H_{fusion}$ = enthalpy change for fusion = $3.35\times 10^5J/Kg$

Now put all the given values in $Q_1$ , we get:

$Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J$

For process 2 :

$Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})$

where,

$Q_2$ = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

$c_{p,l}$ = specific heat of liquid water = $4186J/Kg^oC$

$T_1$ = initial temperature = $0^oC$

$T_2$ = final temperature = $100^oC$

Now put all the given values in $Q_2$ , we get:

$Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC$

$Q_2=4.186\times 10^5J$

From this we conclude that, $Q_1$ that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

5 0

3 years ago

Interpreting the periodic table

Goryan [66]

Here is an image of the periodic table. Hope this helps.

6 0

3 years ago

Listed below are blood groups of o, a, b, and ab of randomly selected blood donors (based on data from the greater new york bloo

KIM [24]

The answer to this is 22, confirmed by gradpoint

3 0

3 years ago

Read 2 more answers

A gas occupies a 1.5 L container at 25 degrees Celsius and 2.0 atm. If the gas is transferred to a 3.0 L container at the same t

harkovskaia [24]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

P2 = P1 x V1 / V2

P2 = 2.0 x 1.5 / 3

P2 = 1 atm

4 0

3 years ago

Read 2 more answers

Write the electronic configuration of 6c element and state the group,period to which it belongs​

Write the electronic configuration of 6c element and state the group,period to which it belongs