Answer:
es este 167 es el te d ultado espero te ayude
Answer:
The correct option is: (D) All of the above
Explanation:
An atomic orbital is the three-dimensional space or region around the nucleus of an atom, where the probability of finding an electron is maximum.
The s-orbitals are the atomic orbitals that have azimuthal quantum number, l = 0. These atomic orbitals have <u>spherical shape and symmetry.</u>
The p-orbitals are the atomic orbitals that have azimuthal quantum number, l = 1. These atomic orbitals have a <u>dumbbell shape.</u>
The atomic orbitals that are closer to the nucleus, have lower energy. Therefore, we can say that the <u>s-orbitals are lower in energy than the p-orbitals.</u>
Answer:
P = 995.6 atm
Explanation:
assuming ideal gas:
∴ Tst = 25°C ≅ 298 K
∴ V = 35.00 mL = 0.035 L
∴ molar mass CO2 = 44.01 g/mol
∴ mass CO2(g) = 62.76 g
⇒ mol CO2(g) = (62.76 g)*(mol/44.01 g) = 1.426 mol
∴ R = 0.082 atm.L/K.mol
⇒ P = RTn/V
⇒ P = ((0.082 atm.L/K.mol)*(298 K)*(1.426 mol)) / (0.035 L)
⇒ P = 995.6 atm
C₂HO₂Br₃
Explanation:
Given parameters:
Carbon = 8.09%
Hydrogen = 0.34%
Oxygen = 10.78%
Bromine = 80.78%
Unknown:
Empirical formula = ?
Solution:
The empirical formula is the simplest formula of a compound.
To find it, we use the process below:
C H O Br
Percent
compo-
sition 8.09 0.34 10.78 80.78
Molar
mass 12 1 16 80
Numb-
of moles 8.09/12 0.34/1 10.78/16 80.78/80
0.68 0.34 0.68 1
Divide
by
smallest 0.68/0.34 0.34/0.34 0.68/0.34 1/0.34
2 1 2 3
Empirical formula C₂HO₂Br₃
learn more:
Empirical formula brainly.com/question/2790794
#learnwithBrainly
250 --> 125 --> 62.5 --> 31.25
each arrow equals one half life, so 3 half lives
14 days/ 3 half lives =
4.67 days = half life
