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melomori [17]
3 years ago
13

The expected value for a chemical equation is 47g of water, after an experiment you find that you have 2.58 moles of water. What

is the actual yield of your chemical reaction? *
Chemistry
1 answer:
strojnjashka [21]3 years ago
6 0
<h3><u>Answer</u>;</h3>

Actual yield = 46.44 g

<h3><u>Explanation;</u></h3>

1 mole of water = 18 g/mol

Therefore;

The experimental yield = 2.58 moles

equivalent to ; 2.58 × 18 = 46.44 g

The theoretical value is 47 g

Percentage yield = 46.44/47 × 100%

                             = 98.8%

The questions asks for actual yield = 46.44 g

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A gas occupies a volume of 67.54 liters at 158°C and 4.87 atm pressure. Calculate the number of moles of this gas.
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Answer:

The number of moles of the gas is 9.295 moles or 9.30 moles

Explanation:

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The first-order rate constant for the decomposition of N2O5:
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Answer:

0.0055 mol of N2O5 will remay after 7 min.

Explanation:

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0.0117 = 3.8644y

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