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Cloud [144]
3 years ago
9

Please help! Which atoms represent different isotopes of the same element? Picture included

Chemistry
1 answer:
posledela3 years ago
5 0

"Option C" O¹⁵8 and O¹⁶8 atoms represent different isotopes of the same element.

Hope it helps...

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At a certain temperature the vapor pressure of pure heptane (C_7 H_16) is measured to be 170. torr. Suppose a solution is prepar
steposvetlana [31]

Explanation:

The given data is as follows.

       Pressure (P) = 170 torr,      mass of heptane (m) = 86.7 g

First, we will calculate the number of moles as follows.

          No. of moles = \frac{mass}{\text{molar mass}}

                        = \frac{86.7 g}{100 g/mol}

                        = 0.867 mol

Now, the number of moles of CH_{3}COBr are calculated as follows.

     No. of moles =  \frac{mass}{\text{molar mass}}

                           =  \frac{125}{122.9}    

                           = 1.07

Therefore, mole fraction of heptane will be calculated as follows.

     Mole fraction = \frac{\text{moles of heptane}}{\text{total moles}}

                           = \frac{0.867}{0.867 + 1.07}

                           = \frac{0.867}{1.937}

                           = 0.445

Now, we will calculate the partial pressure of heptane as follows.

            P_{A} = x_{A}P^{o}_{A}

                 = 170 \times 0.445      

                 = 75.65 torr

Thus, we can conclude that the partial pressure of heptane vapor above this solution is 75.65 torr.

8 0
4 years ago
_ is the process in which an element spontaneously transforms into another isotope of the same element, or into a different elem
MariettaO [177]

Answer:

Nuclear transmutation

Explanation:

The process in which an element spontaneously transforms into another isotope of the same element, or into a different element is called nuclear transumutation. It occurs when the number of protons or neutrons in the nucleus of an atom is changed.

8 0
3 years ago
A gas occupies 1200 litres at 2 atm pressure. To what pressure must it be compressed to occupy 60 litres at the same temperature
MArishka [77]

P2 = 40 atm

Explanation:

Given:

P1 = 2 atm

V1 = 1200 L

V2 = 60 L

P2 = ?

Using Boyle's law and solving for P2,

P1V1 = P2V2

P2 = (V1/V2)P1

= (1200 L/60 L)(2 atm)

= 40 atm

8 0
3 years ago
Calculate the value of ΔG∘rxnΔGrxn∘ for the following reaction at 296 K. Ka = 2.9 × 10–8 and assume Ka does not change significa
oee [108]

Answer:

\Delta G_{rxn}=42.7\frac{kJ}{mol}

Explanation:

In this case, for the dissociation of hypochlorous acid, we know that the acid dissociation constant (Ka) is 2.9x10⁻⁸, which is related with the Gibbs free energy as shown below:

\Delta G_{rxn}=-RTln(K)

But in this case K is just Ka, therefore, at 296 K, it turns out:

\Delta G_{rxn}=-8.314\frac{J}{mol*K}*296K*ln(2.9x10^{-8})\\\\\Delta G_{rxn}=42.7\frac{kJ}{mol}

Such result, means that the reaction is nonspontaneous at the given temperature, it means it is not favorable (not easily occurring).

Best regards.

7 0
3 years ago
I am confused on how to solve
Mumz [18]
What do you need help on
8 0
3 years ago
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