Explanation:
( a )
The decomposition reaction of KClO₃ to form diatomic oxygen gas is the following way -
2  KClO₃ ( s )  -------> 2 KCl ( s ) +  3O₂ ( g )
( b )
The reaction of solid metal of Aluminum with Iodine in the following way -
2 Al ( s )  +  3 I₂ ( s ) ------> Al₂I₆ ( s )
( c )
The reaction of sodium chloride with aqueous sulfuric acid is as follow -
2 NaCl ( s )   +  H₂SO₄ ( aq ) ------>  2 HCl ( g ) +  Na₂SO₄ ( aq )
( d )
The reaction of phosphoric acid with potassium hydroxide , in the following way -
H₃PO₄ ( aq ) + KOH ( aq ) ------> KH₂PO₄ ( aq ) + H₂O ( l )
 
        
             
        
        
        
Mass of solute = 25.8 g
mass solution = 212 g
% =(  mass of solute / mass solution ) x 100
% = ( 25.8 / 212 ) x 100
% = 0.122 x 100
= 12.2 %
        
                    
             
        
        
        
In humans, height, skin color, hair color, and eye color are examples of polygenic traits.
A polygene is a member of a collection of non-epistatic genes that interact additively to steer a phenotypic trait, consequently contributing to more than one-gene inheritance, a sort of non-Mendelian inheritance, in preference to unmarried-gene inheritance, which is the core belief of Mendelian inheritance.
A polygenic trait is a feature, which includes height or skin coloration, that is encouraged by way of or extra genes. because a couple of genes are concerned, polygenic developments do not comply with the styles of Mendelian inheritance. Many polygenic traits are also stimulated by means of the environment and are called multifactorial.
Most inherited trends in animals are polygenic. a few examples are: conformation, kind, size, sturdiness, disorder resistance, temperament, velocity, milk and egg production, growth fee, maturation and sexual adulthood rate, and numerous inherited diseases.
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The mass in grams of butane at standard room temperature is 53.21 grams.
<h3>How can we determine the mass of an organic substance at room temperature?</h3>
The gram of an organic substance at room temperature can be determined by using the ideal gas equation which can be expressed as:
PV = nRT
- Pressure = 1.00 atm
 - Volume = 22.4 L
 - Rate = 0.0821 atm*L/mol*K
 - Temperature = 25° C = 298 k
 
1 × 22.4 L = n × (0.0821 atm*L/mol*K×  298 K)
n = 22.4/24.4658 moles
n = 0.91556 moles
Recall that:
- number of moles = mass(in grams)/molar mass
 
mass of butane = 0.91556 moles × 58.12 g/mole
mass of butane = 53.21 grams
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