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Leona [35]
3 years ago
15

What is the slope of the line that passes through the points (–2, 5) and (1, 11)? A. B. C. D.

Mathematics
1 answer:
Zina [86]3 years ago
5 0

None of those choices is correct.

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Find the distance between the two endpoints.<br> (-6, 1) and (-3, 1)
AleksAgata [21]

Answer:

3

Step-by-step explanation:

distance formula

3 0
2 years ago
Which statement must be true
monitta

Answer:

(C)

Step-by-step explanation:

AD and BC are parallel to each other. They are the same distance but they never touch.  

Your best answer would be C.

Brainilest appreciated.

4 0
3 years ago
How many solutions does the following equation have? <br><br>-6(x+7) = -4x -2​
Fed [463]
Solve for x first
-6x - 42 = -4x -2
-6x = -4x + 40
- 2x = 40
X = -20
The equation has one solution
3 0
2 years ago
Evaluate the expression when x=3 and y=-6<br> 7y-x
Alenkasestr [34]
7(-6) - 3
-42 -3
-45
Your answer is -45
8 0
3 years ago
Read 2 more answers
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
3 years ago
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