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Svet_ta [14]
3 years ago
8

Can you help me in question 30?!

Mathematics
2 answers:
patriot [66]3 years ago
7 0

Answer:   24

Step-by-step explanation:

Kisachek [45]3 years ago
5 0

Answer:

24

Step-by-step explanation:

Volume is length times width times height so you just have to multiply 3 by 4 by 2 to get 24.

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Write the equation of the parabola in vertex form.
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F(x) = 5(x - 3) + 1

Find slope by using the vertex point and the other point given. You get 5. Then the vertex point is just the opposite x and the number after the parentheses.
3 0
3 years ago
What is the measure of an angle that is the supplement of angle C?
Margaret [11]

Answer:

15

Step-by-step explanation:

5 0
3 years ago
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Solve. 12 students in the classroom and she wants to create a student to teacher ratio of three to one (three students per teach
Natasha2012 [34]
She will need a one to one ratio so to get to your ratio you need to take your 3 to 1 ratio and divide it by the 1 on 1 ratio 
7 0
4 years ago
300 pounds of oranges were purchased at $0.24 per pound. The desired markup is 50% based on selling price, but 21% spoilage is e
andrezito [222]
1. The problem indicates that 300 pounds of oranges were purchased at $0.24 per pound, so the cost is:
 
 300x$0.24=$72
 
 2. A percent of 21% spoilage is expected, which means that 89% of 300 pounds of oranges left, is:
 
 300x0.89=267 pounds of oranges
 
 3. We want to calculate the selling price per pound of 267 pounds of oranges, so let's call this value "x":
 
 Markup %=(Markup/cost)x100
 
 Markup=267x-72
  
 4. The desired markup, based on selling price, is 50%. So, when we substitute the values, we obtain:
 
 (267x-72/72)x100=50
 
 5. Let's clear the "x":
 
 (26700x-7200/72)=50
 26700x-7200=50x72
 26700x-7200=3600
 26700x=3600+7200
 x=10800/26700
 x=$0.40
 x=40 cents
 
 What should the selling price per pound be?
 
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8 0
4 years ago
There is a line that includes the point (4, 1) and has a slope of 1/4. what is its equation in
Lelechka [254]

Answer:

y=1/4x

Step-by-step explanation:

y=mx+b

m=1/4

so, y=1/4x+b

Now, look at our line's equation so far: . b is what we want, the 1/4 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (4,1).

So, why not plug in for x the number 4 and for y the number 1? This will allow us to solve for b for the particular line that passes through the point you gave!.

(4,1). y=mx+b or 1=1/4 × 4+b, or solving for b: b=1-(1/4)(4). b=0.

y=1/4x+0

3 0
3 years ago
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