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igor_vitrenko [27]
2 years ago
10

I have no clue how to do this need help

Mathematics
1 answer:
ch4aika [34]2 years ago
4 0

Answer:

  P(x, y) = (√3/2, -1/2)

Step-by-step explanation:

There are a few special angles whose trig functions are worthwhile to remember. The top half of the table in the second attachment shows these.

The first attachment shows a unit circle and coordinates of the points at these special angles. It is worthwhile to remember there are 2π radians in a circle, so -π/6 radians (your angle) corresponds to a positive angle of 11π/6 radians.

__

The coordinates of P are ...

  P(x, y) = (√3/2, -1/2)

_____

<em>Additional comment</em>

The coordinates of any point at angle α on a unit circle are ...

  (x, y) = (cos(α), sin(α))

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The area of a square is given by the expression square inches. Find an expression that represents the length of one side of the
Verizon [17]

Answer:

A. x-6

Step-by-step explanation:

The area of a square is given by the expression x^2-12x+36 square inches. Now we need to find an expression that represents the length of one side of the square, in inches. To do that we need to factor x^2-12x+36.

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Since area of square is given by (side)^2

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3 years ago
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The correct answer is 0.6 :)
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3 years ago
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Lapatulllka [165]

Answer:

212 more student voted musical than drama .

Step-by-step explanation:

As given

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\bf \qquad \qquad \textit{ratio relations}&#10;\\\\&#10;\begin{array}{ccccllll}&#10;&Sides&Area&Volume\\&#10;&-----&-----&-----\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}&#10;\end{array} \\\\&#10;-----------------------------\\\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\&#10;-------------------------------\\\\

\bf \cfrac{small}{large}\quad \stackrel{area~ratio}{\cfrac{s^2}{s^2}}\implies \stackrel{area~ratio}{\cfrac{x^2}{(5x)^2}}\implies \stackrel{area~ratio}{\cfrac{x^2}{5^2x^2}}\implies \stackrel{area~ratio}{\cfrac{\underline{x^2}}{25\underline{x^2}}}=\stackrel{area~ratio}{\cfrac{35}{a}}&#10;\\\\\\&#10;\cfrac{1}{25}=\cfrac{35}{a}\implies a=\cfrac{25\cdot 35}{1}
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