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cestrela7 [59]
2 years ago
13

I just need the edges, correct answer gets brainliest

Mathematics
2 answers:
Aleonysh [2.5K]2 years ago
6 0

Answer:

28

Step-by-step explanation:

counting all the lines pretty much

Feliz [49]2 years ago
3 0

Answer:

its 8x3 for edges so 24 and its 8x2 for vercicles its 16 but for the faces its 8+2 = 10 so you are chillin :)

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(Do only the number line) just tell me what to write after the 0 I don't understand the number line
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6 0
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Jocelyn owns a food truck that sells tacos and burritos. She only has enough supplies to make 150 tacos or burritos. She sells e
timurjin [86]

Answer:

We know that:

Price of a taco = $4

Price of a burrito = $6.50

x = number of tacos sold

y = number of burritos sold.

We must have that:

x + y ≤ 150  (Because she only has supplies to make 150 tacos or burritos, but she can sell less than that)

And also we know that she must sell at least $780, then:

x*$4 + y*$6.50 ≥ $780

Now we found the system of inequalities:

x + y ≤ 150

x*$4 + y*$6.50 ≥ $780

To solve it graphically, we just need to find each one of the region solutions for each equation, and the intersection of these regions will be the solution for the system.

To graph them may be easier to write them as lines, you can do it as follows:

y ≤ 150 - x

y ≥ ($780 - x*$4)/$6.50

in the first equation, we will shade the area below the line, and in the second equation, we will shade the area above the line.

You can see the image below.

Where the accepted solutions are the ones in the darker part, and we only restrict this to positive values of x (because of how we defined the variable x)

Then looking at the image, we can see that one solution can be the point

x = 20, y = 120

7 0
3 years ago
At a production process, the produced items are tested for defects. A defective unit is classified as such with probability 0.9,
Snezhnost [94]

Answer:

We use Baye's theorem:  P(A)P(B|A) = P(B)P(A|B)

with (A) being defective and

(B) marked as defective

we have to find P(B) = P(A).P(B|A) + P(¬A)P(B|¬A). .......eq(2)

Since  P(A) = 0.1 and P(B|A)=0.9,

P(¬A) = 1 - P(A) = 1 - 0.1 = 0.9

and

P(B|A¬) = 1 - P(¬B|¬A) = 1 - 0.85 = 0.15

put these values in eq(2)

P(B) = (0.1 × 0.9) + (0.9 × 0.15)

       = 0.225 put this in eq(1) and solve for P(B)

P(B) = 0.4

6 0
3 years ago
NO ONE IS HELPINNGGGG PLZZZZ 30 PTS +brainliest
NikAS [45]

Answer:

studyyy that is allll

Step-by-step explanation:

study

4 0
3 years ago
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