Let’s suppose PT is equal to TQ
Therefore the equations will be equal
3x+7=8x-8
3x-8x=-7-8
-5x=-15
x=3
We have found x now we will substitute it into each equation
PT=3(3)+7
PT=9+7
PT=16
Then we will substitute the second equation
TQ=8(3)-8
TQ=24-8
TQ=16
And here is the answer please correct me if I’m wrong
Answer:
( About ) 1,099 pounds
Step-by-step explanation:
The force required to keep this truck from rolling down the hill is opposed by the force of friction, comparative to the 2600 pounds of force against this friction. It should be that this opposing force is at work more towards the bottom of this hill, and thus the question asks the magnitude of latter force to keep this truck idle -
|| F || = sin( 25 ) * ( Fg ) = sin( 25 ) * ( 2600 lb ) = ( About ) 1098.80748 pounds
<u><em>This can be rounded to a solution of 1099 pounds</em></u>
Answer:
Step-by-step explanation:
triangle: a+b>c. If two lengths are put together, and equals more than the length of the third side, then it's a triangle
right triangle: a2+b2=c2 if the square of the two lengths equal the square of the third, then it's a right triangle
acute triangle: a2+b2>c2 if the square of the two lengths are greater than the square of the third it's acute
obtuse triangle:a2+b2<c2 if the square of the two lengths are less than the square of the third it's obtuse
