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lianna [129]
2 years ago
6

True Value Rentals charges $20 to rent a moving

Mathematics
2 answers:
Mariulka [41]2 years ago
8 0
$63 dollars is the answer
vodka [1.7K]2 years ago
3 0

Answer:

$63

Step-by-step explanation:

The answer is $63.00 dollars

I hope is helps

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Find the value of x below
ehidna [41]

Answer:

x=58 degrees

Step-by-step explanation:

The angle DB is equal to 90 degrees, so if you subtract 32 from 90 you get x, which is 58.

3 0
3 years ago
What were the other new Twelves talking about at school?
uranmaximum [27]

Answer:

B.about their first day of training

Step-by-step explanation:

4 0
3 years ago
If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)​
Dahasolnce [82]

Answer:  195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

=(8/15+1)/(1-cosα)= 23/(15*(1-cosα))    (1)

As known cos²α=1-sin²α   (divide by cos²α both sides of equation)

cos²a/cos²α=1/cos²α-sin²α/cos²α

1=1/cos²α-tg²α

1/cos²α=1+tg²α

cos²α=1/(1+tg²α)

cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=

=+-sqrt(225/289)=+-15/17   (2)

Substitute in (1) cosα  by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0
3 years ago
Simplify the expression fraction with numerator of the square root of negative one and denominator of the quantity three plus ei
Ainat [17]
The right answer for the question that is being asked and shown above is that: "fraction with numerator negative 3 minus i and denominator 10." This is the simplified expression fraction with numerator of the square root of negative one and denominator of the quantity three plus eight times i minus the <span>quantity two plus five times i.</span>
5 0
3 years ago
Read 2 more answers
Multiply Conjugates <br><br><br><br><br> (r+1/4)r-1/4)
Mamont248 [21]

Answer:

\large\boxed{\left(r+\dfrac{1}{4}\right)\left(r-\dfrac{1}{4}\right)=r^2-\dfrac{1}{16}}

Step-by-step explanation:

\text{Use}\ (a+b)(a-b)=a^2-b^2\\\\\left(r+\dfrac{1}{4}\right)\left(r-\dfrac{1}{4}\right)=r^2-\left(\dfrac{1}{4}\right)^2=r^2-\dfrac{1^2}{4^2}=r^2-\dfrac{1}{16}

8 0
3 years ago
Read 2 more answers
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