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2 years ago

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48/64 Which choices are equivalent to the fraction below? Check all that apply. A. 8/6 B. 3/4 C. 6/8 D. 12/16 E. 9/12 F. 24/32

2 answers:

daser333 [38]2 years ago

6 0

B, C, D, F are the answers :)

irinina [24]2 years ago

5 0

Answer:

B, C, D, F

Step-by-step explanation:

to simplify the fraction 48/64, you need to divide both the numerator and denominator by their common factors. B is correct since you can divide both by 16, C is correct since both are divisible by 8, D is correct since both are divisible by 4, and F is correct since both are divisible by 2. A, however, would be correct only if the fraction were 64/48 and E would only be correct if 9 was a factor of 48 and 12 was a factor of 64, however neither haev such factors.

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After how many months will colony 2 always have more bacteria than colony 1?

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The true statement is that colony 2 will always have more bacteria than colony 1 after 4 months

<h3>How to determine the number of months?</h3>

The functions are given as:

Colony 1: f(x) = x^2
Colony 2: g(x) = 2^x

When colony 2 has more bacteria than colony 1, then it means that:

g(x) >f(x)

Substitute the function values

2^x > x^2

From the graph of both functions, we have:

2^x > x^2 at x >4

This means that colony 2 will always have more bacteria than colony 1 after 4 months

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2 years ago

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3 years ago

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2 years ago

In ΔABC, m∠1=70° and m∠4=35°. What is m∠3?

11Alexandr11 [23.1K]

Answer:

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Step-by-step explanation:

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8 0

2 years ago

Consider the probability that exactly 20 out of 309 people will get the flu this winter. Choose the best description of the area

noname [10]

Answer:

The distribution of proportion of people who will get the flu this winter is <em>N</em> (0.065, 0.014²).

Step-by-step explanation:

Let <em>X</em> = number of people who will get flu this year.

The sample selected is of size, <em>n</em> = 309.

The number of people who will get flu in this sample is, <em>x</em> = 20.

Compute the sample proportion of people who will get flu as follows:

$p=\frac{x}{n}=\frac{20}{309}=0.065$

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 309 and <em>p</em> = 0.065.

The sample size is quite large, i.e. <em>n</em> = 309 > 30.

And the probability of success is low.

So the Normal approximation to Binomial can be used to approximate the distribution of sample proportion is:

np ≥ 10
n(1 - p) ≥ 10

Check whether the conditions are fulfilled or not as follows:

$np=309\times 0.065=20.085>10\\n(1-p)=309\times (1-0.065)=288.915>10$

Hence, the conditions are fulfilled.

The sampling distribution of sample proportion is:

$p=N(p, \frac{p(1-p)}{n})$

Compute the mean and variance as follows:

$Mean=p=0.065\\Variance=\frac{p(1-p)}{n}=\frac{0.065(1-0.065)}{309}=0.014^{2}$

Thus, the distribution of proportion of people who will get the flu this winter is <em>N</em> (0.065, 0.014²).

6 0

3 years ago