Given:
Sample space be S = 1, 2 ,3 , 4, 5, 6.
The outcomes are equally likely.
To find:
The probability of the event E ="an even number".
Solution:
We have,
Sample space is S = 1, 2 ,3 , 4, 5, 6.
So, the total number of outcomes is 6.
E ="an even number".
E = {2,4,6}
So, the total number of favorable outcomes is 3.
The probability of the event E is
![P(E)=\dfrac{Favorable outcomes}{Total outcomes}](https://tex.z-dn.net/?f=P%28E%29%3D%5Cdfrac%7BFavorable%20outcomes%7D%7BTotal%20outcomes%7D)
![P(E)=\dfrac{3}{6}](https://tex.z-dn.net/?f=P%28E%29%3D%5Cdfrac%7B3%7D%7B6%7D)
![P(E)=\dfrac{1}{2}](https://tex.z-dn.net/?f=P%28E%29%3D%5Cdfrac%7B1%7D%7B2%7D)
![P(E)=0.5](https://tex.z-dn.net/?f=P%28E%29%3D0.5)
Therefore, the probability of the event E is 0.5.