Answer:
linkage with approximately 33 map units between the two gene loci
Explanation:
If two genes are not linked, number of recombinants and parental offspring will be equal. Here it is clearly visible that recombinants are less than parental offspring hence the genes are linked. Given, the offspring are in following numbers:
AaBb = 106 = Parental
aabb = 94 = Parental
Aabb = 48 = Recombinant
aaBb = 52 = Recombinant
Recombination frequency = (Number of recombinants/ Total progeny) * 100 = (100/300) * 100 = 33.33 %
1% recombination frequency= 1 map unit of distance between the two gene loci. So here the distance between the two gene loci is approximately 33 map units.
Hence, these results are consistent with linkage with approximately 33 map units between the two gene loci
The answer is B, sameness
Answer:
The answer is 25 chromosomes.
Explanation:
The chromosomes of a cell are in the cell core. They convey the hereditary data. Chromosomes are comprised of DNA and protein consolidated as chromatin. Every chromosome contains numerous genes.In the core of every phone, the DNA particle is bundled into string like structures called chromosomes. Every chromosome is comprised of DNA firmly looped ordinarily around proteins considered hi-stones that help its structure
Answer:
Leads to variations. Variations which are desirable often show hybrid vigour. High adaptability of individuals to changing environmental conditions. Variations provide a basis for evolutionary changes. The population can increase rapidly when the conditions are favourable. Only one parent is needed. It is more time and energy efficient as you don't need a mate. It is faster than sexual reproduction.
Explanation:
