3x8+4 because 3 times so that is 3 x the sum of 8 and 4 so 8+4 together it would be 3x8+4
5a+5b because 6a-a=5a and 8b-3b=5b. 5a+5b.
The area of the entire circle is pi*(7)^2, or 49pi.
Due to the 90 degree angle, the area of the larger blue sector is
90
------- * 49 pi = 49/4 units^2
360
The area of the smaller blue sector is
48
------- 49 pi = (2/15)(49 pi) = 98 pi/15 units^2
360
The total area of the blue sectors is the sum of 98 pi/15 and 49 pi/4 (units^2):
59 units^2
12
Remember to use PEMDAS when solving these problems. You multiply before you work with addition and subtraction.
(7) m∠A = 52°
(8) m∠B = 117°
Solution:
(7) Let us first define the supplementary and complementary angles.
Supplementary angles: Two angles are said to be supplementary angles if their sum is add up to 180°
Complementary angles: Two angles are said to be complementary angles if their sum is add up to 90°
Given supplement of 142° = 180° – 142°
= 38°
Complement of ∠A = Supplement of 142°
⇒ Complement of ∠A = 38°
Measure of ∠A = 90° – 38°
= 52°
Hence m∠A = 52°.
(8) Given complement of 27° = 90° – 27°
= 63°
Supplement of ∠B = Complement of 27°
⇒ Supplement of ∠B = 63°
Measure of ∠B = 180° – 63°
= 117°
Hence m∠B = 117°.
