The probability that a randomly selected cable repair visit will take at least 43 minutes will be 88%.
Given: The times required for a cable company to fix cable problems in its customers' homes are uniformly distributed between 40 minutes and 65 minutes.
It can be deduced that the probability that a randomly selected cable repair visit will take at least 43 minutes will be calculated thus:
= 1 - [(43 - 40)/(65 - 40)
= 1 - 0.12
= 0.88
Hence, The probability that a randomly selected cable repair visit will take at least 43 minutes will be 88%.
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Answer:
wheres the question? it just says what you said-
Answer:168
Step-by-step explanation: First you do 82 times 3.75 which is 307.50. Then you do 2071.5 - 307.5 = 1764 Then you do 1764 divided by 10.50 which is 168
Answer: Choice C
Graph with filled in circles at d = 0 and d = 2, shading in between
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Explanation:
d = amount downloaded in gigabytes
The smallest amount is d = 0. We cannot download a negative amount of data, so this is why d = 0 is the smallest.
The largest amount allowed is d = 2. This is the cap that the ISP has set up.
So basically d can be anything between d = 0 and d = 2, including both endpoints. This means
We use filled in circles for both endpoints to show to the reader "include these endpoints". Shading is done in between to show the entire solution set of possible d values. For instance d = 1 is in that region so it is possible to have this solution. Something like d = 4 is outside the region and not possible.
Evaluating the given sequence, it is evident that the next number is twice the number prior to it. Thus, the given is a geometric sequence with first term (a1) equal to 1 and common ratio of 2. The geometric series may be calculated by the equation,
Sn = a1 x (1 - r^n) / (1 - r)
where Sn is the sum of n terms in this case, n = 11.
Substituting the known values,
<span> Sn = 1 x (1 - 2^11) / (1 - 2) = 2047
</span>
Thus, S11 is 2047.
