Answer:
converges
Step-by-step explanation:
well the two polynomials in the series are 1 and n^8 (I'm assuming the +7 is not in the decimal but it seems to not matter). The degree of the polynomial 1 is 0 which can be represented by 1x^0. The second polynomial in the denominator has a degree of 8. So j = 0 and k = 8. Since 0 < (8-1)
0 < 7 the series converges
Since 2 and 11 are prime we have
(2x 1)(1x 11) or
(2x 11)(1x 1)
we just need to figure out the signs
remember
(ax+b)(cx+d)=acx^2+bcx+adx+bd
the middle term coeficient is bc+ad
so
2x times 11=22x
1x times 1=x
there is not way to add or subtract 22x and x to get -9x
1st one is wrong
(2x 11)(x 1)
2x times 1=2x
11 times x=11x
11x-2x=9x
the 2x or the 1 has to have the negative
(2x+11)(x-1)
Answer:
n = -14
Step-by-step explanation:
Let us try to solve this equation for n;
3x + 1 - 9 = 3(x + 2) + n
3x - 8 = 3x + 6 + n
3x - 3x -8 - 6 = n
-14 = n
The value of n = -14
This value is the value of the equation that will have no solution.
To know if we are correct, let us input this value into the expression
3x + 1 - 9 = 3(x + 2) + n
3x - 8 = 3x + 6 -14
Collect like terms;
3x - 3x = 8 + 6 - 14
0 = 0
