All categories

1 year ago

Write any four rational numbers between ─5 and ─4.

Mathematics

2 answers:

Lera25 [3.4K]1 year ago

4 0

The rational numbers between -5 and -4 are as follows:

-4.2
- 4.8
- 4.4
- 4.6

<h3>What are rational numbers?</h3>

Rational numbers are numbers that can be expressed as the ratio of two integers. These numbers are in the form of p/q, where p and q can be any integer and q ≠ 0.

Therefore, the rational numbers between -5 and -4 are as follows:

-4.2
- 4.8
- 4.4
- 4.6

Note the numbers are between -5 and -4.

learn more on rational numbers here: brainly.com/question/17450097

#SPJ2

Rasek [7]1 year ago

3 0

Answer:

Step-by-step explanation:

Write any four rational numbers between ─5 and ─4.

-4.1,

-4.2,

-4.3,

-4.4,

-4.5

You might be interested in

Which of the equations shown have infinitely many solutions? Select all that apply.

inna [77]

abcdefghijklmnopqrstuvwxyz

6 0

2 years ago

Read 2 more answers

Your dinner at a restaurant costs $13.65 after you use a coupon for a 25% discount. You leave a tip for $3.00.

slamgirl [31]

Answer:

Step-by-step explanation:

cuz I said so also show me your cake

3 0

2 years ago

Change the following decimal to a fraction. Express your answer like the following example (ex: 9.5 = 9 1/2) 4.125 = ?

user100 [1]

Step-by-step explanation:

$4 + \frac{125}{1000} = 4 + \frac{1}{8} \\ thank \: you$

7 0

2 years ago

Read 2 more answers

ioda

The first one is B4:25

6 0

3 years ago

Read 2 more answers

Suppose we want to choose 5 colors, without replacement, from 8 distinct colors.1. If the order is relevant, how many can be don

Charra [1.4K]

(1) From the information given, if we want to choose 5 colors from 8 distinct colors and the order in which the selection is made is relevant, then what we have is a permutation.

The formula is given as;

$nP_r=\frac{n!}{(n-r)!}$

This formula means we need to select/arrange r items out of a total of n items and the anwer derived would be the total number of arrangements possible.

Therefore, we would have;

$\begin{gathered} nP_r\Rightarrow_8P_5 \\ _8P_5=\frac{8!}{(8-5)!}\Rightarrow\frac{8!}{3!} \\ _8P_5=\frac{8\times7\times6\times\ldots1}{3\times2\times1}\Rightarrow\frac{40320}{6} \\ _8P_5=6720 \end{gathered}$

Therefore, if the order is relevant, this selection can be done in 6,720 ways.

(2) If the order is NOT relevant, then what we need to calculate is a combination and the formula is;

$_nC_r=\frac{n!}{(n-r)!r!}$

The formula can now be applied as follows;

$\begin{gathered} _nC_r\Rightarrow_8C_5 \\ _8C_5=\frac{8!}{(8-5)!\times5!} \\ _8C_5=\frac{8!}{3!\times5!}\Rightarrow\frac{8\times7\times6\times\ldots1}{(3\times2\times1)\times(5\times4\times\ldots1)} \\ _8C_5=\frac{40320}{6\times120} \\ _8C_5=56 \end{gathered}$

If the order is not relevant, then the selection can be done in 56 ways.

3 0

6 months ago