Answer:
11 + x + 19*x
Step-by-step explanation:
The sum of eleven, a number, and the product of nineteen and the number.
we have to read carefully and understand how to interpret
when he says the sum of separates into 3 parts because there is a "comma" and an "and"
Now let's separate the 3 parts of the sum
1 part
says eleven so we just put 11
eleven = 11
2 part
in the text it says that we replace "a number" with x
a number = x
3 part
In this case we simply make the product between the given values
the product of nineteen and the number
19 * x
Now we can accommodate everything and we finish
11 + x + 19*x
You may recognize that ∆WYZ is a 3-4-5 right triangle. Without any work, then
c = 5
_____
If you don't remember that a right triangle with legs 3 and 4 has a hypotenuse of 5, you can compute it using the Pythagorean theorem.
c² = 3² + 4²
c² = 9 + 16 = 25
c = √25 = 5
Answer:
Equations made up of multiple variables like formulas.
Step-by-step explanation:
Similar to how y = mx+b has many letters in it but we can input known values to solve for the values that we want.
Answer:
4,314.6
Step-by-step explanation:
522.98 multiplied by 8.25 is 4,314.585 which rounded to the nearest cent is 4,314.6
Answer:
![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Step-by-step explanation:
The options are missing; However, I'll simplify the given expression.
Given
![\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B32x%5E3y%5E6%7D%7D%7B%5Csqrt%5B3%5D%7B2x%5E9y%5E2%7D%20%7D)
Required
Write Equivalent Expression
To solve this expression, we'll make use of laws of indices throughout.
From laws of indices ![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
So,
gives

Also from laws of indices

So, the above expression can be further simplified to

Multiply the exponents gives

Substitute
for 32


From laws of indices

This law can be applied to the expression above;
becomes

Solve exponents


From laws of indices,
; So,
gives

The expression at the numerator can be combined to give

Lastly, From laws of indices,
; So,
becomes
![\frac{\sqrt[3]{(2y)}^{4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B%282y%29%7D%5E%7B4%7D%7D%7Bx%5E2%7D)
![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Hence,
is equivalent to ![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)