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borishaifa [10]
3 years ago
9

Which polynomial function has a leading coefficient of 3 and roots –4, i, and 2, all with multiplicity 1? f(x) = 3(x 4)(x – i)(x

– 2) f(x) = (x – 3)(x 4)(x – i)(x – 2) f(x) = (x – 3)(x 4)(x – i)(x i)(x – 2) f(x) = 3(x 4)(x – i)(x i)(x – 2)
Mathematics
1 answer:
Pepsi [2]3 years ago
5 0

The polynomial function with leading coefficient of 3 and root -4, i, and 2 all with multiplicity of 1 is f(x) = 3(x+4)(x-i)(x+2)

<h3>Polynomial function</h3>

The Leading coefficients are the numbers written in front of the variable with the largest exponent.

Roots of a polynomial refer to the values of a variable for which the given polynomial is equal to zero.

The multiplicity is the number of times a given factor appears in the factored form of the equation of a polynomial.

Therefore, the polynomial f(x) = 3(x+4)(x-i)(x+2) has a root -4 , 1 and -2.

The leading coefficient is 3. The multiplicity is all one.

learn more on polynomial here: brainly.com/question/13309002

#SPJ4

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