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Gelneren [198K]
3 years ago
15

19 = 15 w- 4(3 w-1) solve for w

Mathematics
1 answer:
Gnom [1K]3 years ago
8 0

Step-by-step explanation:

Simplifying

19 = 15w + -4(3w + -1)

Reorder the terms:

19 = 15w + -4(-1 + 3w)

19 = 15w + (-1 * -4 + 3w * -4)

19 = 15w + (4 + -12w)

Reorder the terms:

19 = 4 + 15w + -12w

Combine like terms: 15w + -12w = 3w

19 = 4 + 3w

Solving

19 = 4 + 3w

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '-3w' to each side of the equation.

19 + -3w = 4 + 3w + -3w

Combine like terms: 3w + -3w = 0

19 + -3w = 4 + 0

19 + -3w = 4

Add '-19' to each side of the equation.

19 + -19 + -3w = 4 + -19

Combine like terms: 19 + -19 = 0

0 + -3w = 4 + -19

-3w = 4 + -19

Combine like terms: 4 + -19 = -15

-3w = -15

Divide each side by '-3'.

w = 5

Simplifying

w = 5

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Given: ∆PQR, m∠R = 90° m∠PQR = 75° M ∈ PR , MP = 18 m∠MQR = 60° Find: RQ
tensa zangetsu [6.8K]

Answer:    RQ= 8.99 ( approx)

Step-by-step explanation:

Let MR= x

Since, In triangle, PRQ, tan 75°= \frac{18+x}{RQ}

⇒ RQ=  \frac{18+x}{tan 75^{\circ}}

Now, In triangle MRQ,

tan 60°= \frac{18+x}{RQ}

⇒ RQ=  \frac{x}{tan 60^{\circ}}

On equating both values of RQ,

\frac{18+x}{tan 75^{\circ}}=\frac{x}{tan 60^{\circ}}

⇒\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}

⇒\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}

⇒\frac{18+x}{x}=2.15470053838

⇒18=2.15470053838x-x

⇒x=15.5884572681≈15.60

Thus RQ=8.99999999999≈8.99


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