One simple way to approach this is to subtract the number that DOESN’T have the variable with the solution by the sum. Lets use problem 1 as the example: 1.) N+8=13 In this case, we subtract 13 by 8 and get 5, therefore N= 5.
2.) B+17=62 62-17= 45 B= 45
3.) X+5/6= 7/16 7/16-5/6= -19/48 X= -19/48
4.) y+1/7=5/8 5/8-1/7= 27/56 Y= 27/56
5.) 14+y=69 69-14=55 Y=55
6.) c+3.6=4.9 4.9-3.6=1.3 C= 1.3
Now for the word problems: Lets use 7 as the example- 7.) a number increased by 19 is equal to 221. Since we don’t know the number being increased by 19, that will be our variable. It will be re-written as so:
N + 19 = 221
Where N is the unknown number.
Using the same method of subtracting by the sum and the number that’s not the variable, we’ll get the solution to N 221-19= 202 N= 202
Normally when there is similar terms and when you have to figure out if it is factorable or prime you must first begin factoring it and if it does not work it is prime. Hope this helps, ask me if you have any questions.
