One simple way to approach this is to subtract the number that DOESN’T have the variable with the solution by the sum. Lets use problem 1 as the example: 1.) N+8=13 In this case, we subtract 13 by 8 and get 5, therefore N= 5.
2.) B+17=62 62-17= 45 B= 45
3.) X+5/6= 7/16 7/16-5/6= -19/48 X= -19/48
4.) y+1/7=5/8 5/8-1/7= 27/56 Y= 27/56
5.) 14+y=69 69-14=55 Y=55
6.) c+3.6=4.9 4.9-3.6=1.3 C= 1.3
Now for the word problems: Lets use 7 as the example- 7.) a number increased by 19 is equal to 221. Since we don’t know the number being increased by 19, that will be our variable. It will be re-written as so:
N + 19 = 221
Where N is the unknown number.
Using the same method of subtracting by the sum and the number that’s not the variable, we’ll get the solution to N 221-19= 202 N= 202
