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2 years ago

Find the length of a missing side, x , in the triangle at right. Show the work leading to your answer

Mathematics

1 answer:

BARSIC [14]2 years ago

5 0

Answer:

Step-by-step explanation:

!3x5 is 48

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Ivahew [28]

4 over 5 is the correct answer

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3 years ago

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Determine which method works, substitution or elimination? 4x^2+3y^2=42x^2-6y^2=-3

GarryVolchara [31]

Given:

$\begin{gathered} 4x^2+3y^2=4 \\ \\ 2x^2-6y^2=-3 \end{gathered}$

Find the method .

Sol:

$\begin{gathered} 4x^2+3y^2=4..............(1) \\ \\ 2x^2-6y^2=-3.............(2) \end{gathered}$

2eq(1) + eq(2) then,

$8x^2+6y^2=8$

Then apply the elimination method.

$\begin{gathered} 8x^2+6y^2=8 \\ 2x^2-6y^2=-3 \\ --------- \\ 10x^2=5 \\ \\ x^2=\frac{5}{10} \\ \\ x=\sqrt{\frac{1}{2}} \end{gathered}$

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1 year ago

(2x - 1) ft (x + 4) ft 7 ft

anygoal [31]

What is the question?

7 0

3 years ago

Dividing rational expressions

Galina-37 [17]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
\cfrac{x+3}{x^2-2x}\cdot \cfrac{(x-2)^2}{x^2-9}\implies \cfrac{x+3}{x^2-2x}\cdot \cfrac{(x-2)(x-2)}{x^2-3^2}
\\\\\\
\cfrac{x+3}{x(x-2)}\cdot \cfrac{(x-2)(x-2)}{x^2-3^2}\implies \cfrac{\underline{x+3}}{x\underline{(x-2)}}\cdot \cfrac{\underline{(x-2)}(x-2)}{(x-3)\underline{(x+3)}}
\\\\\\
\cfrac{x-2}{x(x-3)}\iff\cfrac{x-2}{x^2-3x}$

5 0

3 years ago

Simplify. y^5 ÷ y^3 × y^2 NEED HELP ASAPP PLEASEEE ??? Will get BRAINLIEST***

Volgvan

Answer:

y^5 ÷ y^3 * y^2 = y^4

Step-by-step explanation:

https://www.symbolab.com/solver/factor-calculator/Simplify%20y%5E%7B5%7D%5Cdiv%20y%5E%7B3%7D%C3%97y%5E%7B2%7D%20

(use that link if you want to see the work for yourself)

3 0

3 years ago