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bonufazy [111]
2 years ago
15

Find the length of a missing side, x , in the triangle at right. Show the work leading to your answer

Mathematics
1 answer:
BARSIC [14]2 years ago
5 0

Answer:

48

Step-by-step explanation:

!3x5 is 48

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Find the missing probability in the table below.
Alla [95]
X          1           2        3         4
p(x)    0.40    0.20   0.15     ?

If the items are only 4. The total of the probability must be 1 or 100%

1 - 0.40 - 0.20 - 0.15 = 0.25

The probability of 4 is 0.25.
7 0
3 years ago
I need help solving number 11 please.
Mnenie [13.5K]

set up the triangle with the information given. then just solve for x.

3 0
3 years ago
I really need to know the answer this fast please!!!!!!
Zepler [3.9K]
The answer is A I think
3 0
3 years ago
A square piece of paper has an area of x2 square units. A
Dmitry_Shevchenko [17]

Answer:

Length of rectangular strip = 12

area of rectangular strip =   2*12 = 24

Area of square =  x^2 = 12^2 = 144

Step-by-step explanation:

Area of square x^2

area of rectangle is given by length * width

Length of rectangular strip = x

width of rectangular strip = 2

area of rectangular strip =  length * width = 2*x = 2x

Area of square piece of paper when  rectangular strip is taken away from it

= Area of square - area of rectangular strip

= x^2 -2x

It is given that Area of square piece of paper when  rectangular strip is taken away from it is 120 square units.

Thus,

x^2 -2x = 120\\=> x^2 -2x -120 = 0\\=> x^2 -12x +10x-120\\=> x(x-12) +10(x-12)\\=> (x+10)(x-12) = 0\\\\

Thus,

either x+10 = 0 or x -12= 0

x = -10 or x = 12

but length cannot  be negative hence neglecting x = -10

hence value of x is 12.

Hence,

Length of rectangular strip = 12

area of rectangular strip =   2*12 = 24

Area of square =  x^2 = 12^2 = 144

5 0
3 years ago
Find the lateral area of a cylinder that has a diameter of 18 mm and a height of 15 mm.​
nika2105 [10]

Answer:

848.23 mm²

Step-by-step explanation:

LA = πdh

LA = 3.14159 × 18 mm × 15 mm

LA = 848.23 mm²

4 0
2 years ago
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