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3 years ago

In the interval 0º < x < 360°, find the values of x for which tan x= -0.6745

Mathematics

1 answer:

Kitty [74]3 years ago

3 0

Step-by-step explanation:

Given interval

0º < x < 360°

tan X = - 0.6745

tan X = tan 146 ° , tan 326

Either

tan X = tan 146

x = 146°

tan X = tan 326°

x = 326°

Therefore the answers are

x = 146° and 326°

Hope it will help :)❤

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For a random sample of 50 measurements on the breaking strength of cotton threads, the mean breaking strength was found to be 21

Vikentia [17]

Answer:

205.81 to 214.19

Step-by-step explanation:

Sample size (n) = 50

Sample mean weight (X) = 210 grams

Sample standard deviation (s) = 18 grams

Confidence coefficient (Z) at 90% = 1.645

The confidence interval for the true mean breaking strength of cotton threads of this type, at a 90% confidence level, is given by:

$CI=X \pm Z*\frac{s}{\sqrt n}\\CI=210 \pm 1.645*\frac{18}{\sqrt 50}\\CI = 210 \pm 4.19\\CI =205.81\ to\ 214.19$

The confidence interval is 205.81 grams to 214.19 grams.

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3 years ago

In a four digit number, the digit in thousand’s place in 4 and the digit in the one’s place is twice that in the thousand’s plac

ale4655 [162]

Answer:

Step-by-step explanation:

As 4 is accumulated by thousands place

And ones place is 4 into 2/twice

And hundreds place accumulates zero

And tens place is 4 - 0=4

The no is

4048

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3 years ago

Dinner for a family of 3 at the local Italian Eatery came to $47.83 before tax. If the family wanted to tip their server 20%, ho

EastWind [94]

Answer:

$9.57

Step-by-step explanation:

47.83 x 20% = 9.57

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3 years ago

Ratio question<br> I will mark brainliest

Usimov [2.4K]

2 m - polyester fabric: 4, cotton fabric: 14

6 m - polyester fabric: 12, cotton fabric: 42

8 m - polyester fabric: 16, cotton fabric: 56

9 m - polyester fabric: 18, cotton fabric: 63

check:

2 m: 4/14=2/7

6 m: 12/42=2/7

8 m: 16/56=2/7

9 m: 18/63 = 2/7

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3 years ago

Of the 8 students in the chess club, three will represent the club at an upcoming competition. How many different 3-person teams

xz_007 [3.2K]

I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have

C(8,3) = 8!/(8-3)!3!
C(8,3) = 56

There are 56 3-person teams that can be formed from the 8 students.

6 0

3 years ago

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