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IRISSAK [1]
3 years ago
5

3 × [ 2 3 × (15 ÷ 3)]

Mathematics
2 answers:
Likurg_2 [28]3 years ago
7 0

Answer:

345

Step-by-step explanation:

3 × [ 2 3 × (15 ÷ 3)]

Work inside out with the parenthesis

3 × [ 2 3 × (5)]

3 × [ 115]

Now we multiply

345

aleksklad [387]3 years ago
4 0

Answer:

345

Step-by-step explanation:

15/3 = 5 so

3 * [23 *(5)]

3*[115]

345

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Caleb is preheating his oven before using it to bake. The initial temperature of the oven is 70° and the temperature will increa
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Answer:

190 Degrees Celsius

Step-by-step explanation:

so first you multiply the

Rate per minute X Minutes

15 X 8 = 120

120 this is the  temperature increase so you add this increase to the initial temperature which was 70 degrees Celsius

temperature Increase + Initial temperature

120 + 70 = 190 degrees Celsius

 

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2 years ago
Round off - 126,945 to the nearest hundred thousand nearest ten thousand nearest thousand which of these rounds amount to the cl
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Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.
Gnoma [55]
For the answer to the question above, I'll explain my answer through an equation below.
<span>5+10>x,x<15
5+x>10
x>10-5
or x>5
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3 years ago
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dedylja [7]

Step-by-step explanation:

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have a gret day too

4 0
3 years ago
Read 2 more answers
The scores on the LSAT are approximately normal with mean of 150.7 and standard deviation of 10.2. (Source: www.lsat.org.) Queen
faltersainse [42]

Answer:

a=150.7 -0.385*10.2=146.773

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.  

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the  scores on the LSAT of a population, and for this case we know the distribution for X is given by:

X \sim N(150.7,10.2)  

Where \mu=150.7 and \sigma=10.2

We want to find a value a, such that we satisfy this condition:

P(X>a)=0.65   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.35 of the area on the left and 0.65 of the area on the right it's z=-0.385. On this case P(Z<-0.385)=0.35 and P(Z>-0.385)=0.65

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

Z=-0.385

And if we solve for a we got

a=150.7 -0.385*10.2=146.773

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.  

5 0
3 years ago
Read 2 more answers
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