You need to spend at least $50 in one day to receive a store discount. You have already spent $30. Let s be the amount of money
(in dollars) you can now spend to qualify for the discount. Which inequality and solution represent this situation?
s+30<50; 8 < 20
s+30 ≤ 50; s ≤ 20
s+30> 50; 8 > 20
s+ 30 ≥ 50; 8 ≥ 20
From the original box and whisker plot, the lower extreme (minimum) is 5 ; The upper extreme, maximum is 15.
The number of batches baked on the eight day is 20. This exceeds tbe previous maximum value. Hence, upper extreme( maximum) value of the new plot will change from 15 to 20.
The lower extreme isn't affected as the obtained value isn't below 5.
The median value will Increase and the upper quartile value will also increase. Once the upper quartile value increases, the interquartile range will also increase