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dimaraw [331]
2 years ago
11

SOMEBODY PLEASE HELP ME!!

Mathematics
1 answer:
notsponge [240]2 years ago
8 0

Answer:

60 square units; 40 units

Step-by-step explanation:

to find the missing side you use the pythagorean theorem

a^2 + b^2 = c^2

8^2 + b^2 = 17^2

64 + b^2 = 289

b^2 = 225

b = 15

area is l*h*1/2

15 * 8 * 1/2 = 60 square units

perimeter is adding them all

15 + 8 + 17 = 40 units

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mihalych1998 [28]

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9.)The usage differs among different disciplines. In statistics probability can be thought of as the inherent chance of something happening, whereas frequency is the observed number of times it has happened, divided by the number of observations.

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3 years ago
Toni pizzeria deposited in checking account,the deposit included 4 fifty-dollar bills, 8 twent dollar bills, 16 ten dollar bills
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Consider the ODE, dy dx = y 2 1 + x (2) subject to condition y = 1 when x = 0, use your Euler code from class (modified if neces
makkiz [27]

Answer:

Computation.

Step-by-step explanation:

I'm not really sure if that's the analytical solution of the inital value problem,

because y(0)=11-ln(1-0)(3)=11. Howevwer, let us procede with the given values...

Let us assume that we are going to use euler with n=2 (two steps) and h=0.2(the size of each step)

The update rules of the Euler Methode are

X_i = X_{i-1}+h=X_0+ih

m_i=\dfrac{dY}{dX} \biggr \rvert_{x_i} \\\\Y_{i+1}=m_i\cdot h+y_i

Since the initial value problem tells us that Y=1 when X=0, we know that

X_0=0 and that Y_0=1. Then, we have

X_0=0\\\\X_1=0.2\\\\X_2=0.4

and

Y_0=1\\\\m_0=21 \cdot Y_0 + X_0 \cdot 2=21 \cdot 1 + 0=21\\\\Y_1=0.2 \cdot 21 + 1 =5.2\\\\m_1=21 \cdot Y_1 + X_1\cdot 2=21 \cdot 5.2 + 0.2 \cdot 2=109.6\\ \\Y_2=m_1 \cdot h + Y_1 = 109.6 \cdot 0.2 + 5.2= 27.12

which gives us the points (0,1), (0.2, 5.2) and (0.4, 27.12).

Now, since we want to compare the analyticaland the Euler result, we first compute the value of y=11-ln(1-x)(3) for the values x=0, 0.2 and 0.4. We get that

y(0)=11-\ln(1-0)(3)=11-ln(1)(3)=11\\\\Y(1)=11-\ln(1-0.2)(3)=11.67\\\\Y(2)=11-\ln(1-0.4)(3)=12.53

and we compute Y(i)-Y_i for each i.

It holds

Y(0)-Y_0=11-1=10\\\\Y(1)-Y_1=11.67-5.2=6.47\\\\Y(2)-Y_2=12.53-27.12=-14.59

which tells us that we have a really bad approximation, as I already stated there must be a mistake in the analytical solution since the intial values don't coincide. Also note that the curve that we get using the euler methose is growing faster than the analitical solution.

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3 years ago
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Which is a correct two-column proof? Given: r || s Prove: ∠b and ∠h are supplementary. Picture 1, Picture 2, Picture 3 or none o
aliina [53]

Answer: The second proof table is the the proper proof table.

We always start out with what we are given, which in this case is r || s saying that r is parallel to s. Also, we always end up with what we want to prove which is angles b and h are supplementary. So this is the last line of the proof.

So far, this eliminates the first proof table because in this table, the last line says "angle c and angle h are supplementary" which is not what we want to end up with. We want the last line to say "angle b and angle h are supplementary".

We can also eliminate the third proof table because of the statement "angle d and angle h are supplementary". They are only supplementary if they are both right angles. Also, the reasoning of "alternate interior angles" is false as they are corresponding angles.

The only thing left is the second proof table which is correctly argued from start to finish.

1. r || s ........................ given

2. angle b = angle c ................ vertical angles

3. c and e are supplementary angles ....... same side interior

4. angle e = angle h ................. vertical angles

5. b and h are supplementary ...... substitution

Note: in line 5, we start with line 3's statement. Then we replace 'c' with 'b', at the same we replace 'e' with 'h'.

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