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barxatty [35]
2 years ago
11

Find the factor of each ff. 49x²-63x+7​

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
7 0

Answer:

7(7x²-9x +1)

Step-by-step explanation:

49x²-63x+7

7(7x²-9x +1)

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Please help I’m doing super bad
Juliette [100K]

Answer:

Choice A: angle 6 and angle 7

Step-by-step explanation:

The meaning of adjacent angles is they are close to each other. That means they share a common point and share a common side.

3 0
3 years ago
A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 10.4
vlabodo [156]

Answer:

Therefore the diameter of the hole is 1.94 \times 10^{-3} m.

Step-by-step explanation:

Bernoulli's equation,

P_1+\frac12 \rho v^2_1+\rho g h_1= P_2+\frac12 \rho v^2_2+\rho g h_2

P₁ = P₂= atmospheric presser

\rho= density

\frac12 \rho v^2_1+\rho g h_1= \frac12 \rho v^2_2+\rho g h_2             [since P₁ = P₂]

\Rightarrow\rho (\frac12 v^2_1+ g h_1)= \rho(\frac12 v^2_2+ g h_2)

\Rightarrow\frac12 v^2_1+ g h_1= \frac12 v^2_2+ g h_2

\Rightarrow\frac12 v^2_2-\frac12 v^2_1=g h_1- g h_2

\Rightarrow v^2_2- v^2_1=2g h                                [h_1-h_2=h]

Here   v_1\approx 0

\Rightarrow v^2_2=2g h

\therefore v_2=\sqrt {2gh

Here g= 9.8 m/s² , h = 10.4 m

The velocity of water that leaves from the hole v_2 = \sqrt {2\times 9.8\times 10.4} m/s

                                                                                  =14.28 m/s.

Given, the rate of flow from the leak is 2.53\times 10^{-3} m^3/min

                                                               =\frac{2.53\times 10^{-3}}{60}  m^3/s

Let the diameter of the hole be d.

Then the cross section area of the hole is =\pi (\frac d2)^2

We know that,

The rate of flow = Cross section area × speed

\Rightarrow \frac{2.53\times 10^{-3}}{60} =\pi (\frac d2)^2\times 14.28

\Rightarrow (\frac d2)^2=\frac{2.53\times 10^{-3}}{60\times 14.28\times \pi}

\Rightarrow d= 1.94 \times 10^{-3}

Therefore the diameter of the hole is 1.94 \times 10^{-3} m.

4 0
4 years ago
What is the following is the solution to the equation 25^(z+2) = 125
maksim [4K]

First, rewrite the equation 25^{z+2} = 125 with the base equal to 5. Note that:

  • 25=5^2;
  • 125=5^3;
  • 25^{z+2}=(5^2)^{z+2}=5^{2\cdot (z+2)}.

Then

5^{2\cdot (z+2)}=5^3.

Since the bases are equal, you have that powers are equal too:

2\cdot (z+2)=3,\\ \\2z+4=3,\\ \\2z=3-4,\\ \\2z=-1,\\ \\z=-\dfrac{1}{2}.

Answer: z=-\dfrac{1}{2}.


3 0
4 years ago
What would the answer be?
gizmo_the_mogwai [7]

At 55 miles per hour, he travels 55 miles in every hour. So, in 2 hours he goes 55 x 2 miles, or 110 miles.

In the same way: at 70 miles per hour he goes 70 miles in every hour, and he only travels for an hour, so he goes 70 miles.

Going 50 mph (miles per hour) for 2 hours, he travels 50 x 2 miles or 100 miles.

Add these numbers up: 110+70+100 = 280.

5 0
3 years ago
An object moves at a constant rate along a circular path with radius 10 inches, and makes 3 revolutions in 2 seconds.
Neko [114]

Answer:

94.28 inches/second.

Step-by-step explanation:

The length of the circumference of the circular path with 10 inches radius is = 2\pi r = 2 \times \frac{22}{7} \times 10 = 62.85 inches.

Now, the point on the edge of the wheel moves by 3 revolutions in 2 seconds.

So, in 2 seconds the point moves a linear distance of (3 × 62.85) = 188.57 inches.

Therefore, the linear velocity of the point in inches per second is \frac{188.57}{2} = 94.28  inches per second.

(Answer)

8 0
3 years ago
Read 2 more answers
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