Log₄32 = ln32/ln4 =3.466/1.386 =5/2 =2.5
Another method log₄(32) = x
Then 32= 4^x
but 32 = 2^5 & 4^x = 2^2x
Then 2^5 = 2^(2x)==> 5=2x & x =5/2
Answer:
240
Step-by-step explanation:
Using long division i got this :
0 2 4 0
3 2 7 6 8 0
− 0
7 6
− 6 4
1 2 8
− 1 2 8
0 0
− 0
0
Hope this helps!
F =del F, make the distinction its 2 different functions
in this case its a conservative vec field
u can do Del x F or curl F and see its not 0, but anyway, u can also integrate the portion in i wrt to x and portion in j component wrt to y, and see that even with the constants being functions of the variable not being integrated wrt to, you still cannot find a function g such that f(x,y)=del (g)
300 (3 hundreds)+20 (2 tens) should equal 320. Greg confused the hundreds place with the tens place and the tens place with the ones place, what he thought was : 3 tens plus 2 ones equals 32. Answer: He got hundreds confused with tens, and tens confused with ones.