The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer: yea you are
Step-by-step explanation:
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Answer:
Solution given;
for sphere
radius [r]:12inches
another
radius [R]:9inches
Now
difference in volume of sphere:
volume of sphere of having radius [r-R]
=
-
=
(12³-9³)
= 1332π cubic inches
The volume of the larger sphere is <u>___1332</u>__π cubic inches greater than the volume of the smaller sphere.