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Strike441 [17]
3 years ago
14

P=2W+2L solve for W​

Mathematics
1 answer:
WARRIOR [948]3 years ago
5 0

Answer:

What's the value for P and L?

Step-by-step explanation:

2W = 2L - P

W = (2L - P) / 2

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Help please! the question is in the picture below for reference when answering! thank you so much!
stepan [7]

Answer:

x = -1

Step-by-step explanation:

AB + BC = AC = 28

the way from A to C goes through B.

so, the total way of A to C is the sum of the way from A to B and then from B to C.

=>

(5x + 10) + (2x + 25) = 28

7x + 35 = 28

7x = -7

x = -1

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F(x) = 4x + 7, g(x) = 3x^2 Find (f + g)(x)
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For the functions f(x) = 4x + 7 and g(x) = -9x + 11, find f(g(0)). For the functions f(x) = 3x2 - 7 and g(x) = -3x2 + 4, find f(g(2)). (Do NOT put commas in large numbers.)
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3 years ago
On a bicycle trail, the city is painting arrows like the one shown below: Upper pointing arrow with height of 15 and length of 1
Luden [163]

Answer:

229.5cm^{2}

Step-by-step explanation:

In order to calculate the area of the arrow we need to calculate the area of the body of the arrow, and then the head of the arrow. The body of the arrow is a rectangle meaning that the area (Ar) can be calculated by multiplying the length by the height like so...

Ar = l * h

Ar = 11cm * 12cm

Ar = 132 cm^{2}

Now we need to find the area of the head of the arrow, which is a triangle and therefore we can use the formula for the area of a triangle (At) which is height times base divided by 2...

At = \frac{h * b}{2}

At = \frac{15cm * 13cm}{2}

At = \frac{195cm^{2} }{2}

At = 97.5cm^{2}

Now we simply add both areas together to calculate the total area of the arrow...

132cm^{2} + 97.5cm^{2} = 229.5cm^{2}

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3 the radius of both bases are the sams
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7. License Plate Laws The Chapter Problem involved passenger cars in Connecticut and passenger cars in New York, but here we con
sergejj [24]

Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.

Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.

let p_{1} be the probability that commercial cars have rear license plates and p_{2} be the probability that connected trucks have rear license plates.

                         Cars                     Trucks                         Total

Total                  2049                    334                             2383

x                          239                      45                                284

p                        0.1166                   0.1347                          0.1191

α=0.05

Hypothesis will be  :

H_{0}:p_{1} =p_{2}

H_{1} :p_{1} < p_{2}

It is a left tailed test at 0.05 significance.

Standard errors of p=\sqrt{p(1-p)/n}

=\sqrt{(0.1191*0.8809)/2383}

=\sqrt{0.1049/2383}        

=0.0066

Test statistic Z=p difference/standard error

=(0.1166-0.1347)/0.0066

=-0.0181/0.0061

=-2.967

p value=0.001505<5%

Since p is less than 5% we reject null hypothesis.

We cannot calculate standard deviation so  we cannot calculate confidence interval.

Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

Learn more about z test at brainly.com/question/14453510

#SPJ4

5 0
2 years ago
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