The question is confusing and all the answers are not there but it is B C and D
Answer : The pH of the solution is, 9.63
Explanation : Given,
The dissociation constant for HCN = 
First we have to calculate the moles of HCN and NaCN.
and,
The balanced chemical reaction is:
Initial moles 0.1116 0.0461 0.08978
At eqm. (0.1116-0.0461) 0 (0.08978+0.0461)
0.0655 0.1359
Now we have to calculate the pH of the solution.
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
Now put all the given values in this expression, we get:
Therefore, the pH of the solution is, 9.63
<span>100 g of KClO3 @ 122.55 g/mol = 0.816 moles of KClO3
by the reaction
2 KClO3 --> 2 KCl & 3 O2
0.816 moles of KClO3 @ 3 moles O2 / 2 moles KClO3 = 1.224 moles of O2 can be made
using molar mass
1.224 moles of O2 @ 32.0 g/mol =
39.2 grams of O2 can be made</span>
Explanation:
It should be decreasing, and the potential energy increasing, since Law of Conversation of Energy, right?
Also, if you think about what happens when it goes down, it loses potential and gains kinetic, so maybe the opposite should happen when it goes up.
<span>Count the number of times it takes to empty a 100ml beaker using it. Divide the amount of water in the beaker by the number of times it took to empty it and you will have a rough approximation of how many mL your eye dropper will hold. Hope this helped!</span>
