Answer:
∇T = -32°C
Explanation:
T1 = 45°C
T2 = 13°C
∇T =?
∇T = change in temperature = final temperature - initial temperature
∇T = T2 - T1
∇T = 13 - 45
∇T = -32°C
The change in temperature is -32°C
The equation looks like this:
KBr + AgNO3 —-> KNO3 + AgBr
The products are potassium nitrate and silver bromide
Lead(II) nitrate will react with iron(III) chloride to produce the precipitate lead(II) chloride as shown in the balanced reaction
2FeCl3(aq) + 3Pb(NO3)2(aq) → 2Fe(NO3)3(aq) + 3PbCl2(s)
Calculating the amount of the precipitate lead(II) chloride each reactant will produce:
mol PbCl2 = 0.050L Pb(NO3)2 (0.100mol/1L)(3mol PbCl2/3mol Pb(NO3)2)
= 0.00500mol PbCl2
mol PbCl2 = 0.050L FeCl3 (0.100mol FeCl3/1L)(3mol PbCl2/2mol FeCl3) = 0.00750mol PbCl2
The reactant Pb(NO3)2 produces a lesser amount of the precipitate PbCl2, therefore, the lead(II) nitrate is the limiting reagent for this reaction.
Answer : False, there will be two lithium and one oxygen atoms in a unit molecular structure of lithium oxide.
Explanation:
Electronic configuration of lithium is :
In order to attain stable electronic configuration it will loose an electron and form positively charge cation.
The electronic configuration of oxygen is:
Oxygen being second most electronegative atom requires two electrons to attain noble gas configuration stability and form negatively charge ion with 2- charge.:
When two atom of lithium and oxygen comes together , one electron from each lithium atom get transferred to an oxygen atom which results in formation of lithium oxide.