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3 years ago

Write the equation for the production of one hexose sugar molecule from carbon dioxide

Chemistry

2 answers:

Naddik [55]3 years ago

5 0

Answer;

6CO2 + 18ATP + 12 NADPH → C6H12O6 + 18ATP + 18Pi + 12NADP+

Explanation;

-The process of Calvin Cycle Synthesizes Hexoses from Carbon Dioxide and Water.

-The ATP and NADPH molecules produced by the light-dependent reactions of photosynthesis power sugar synthesis in the Calvin cycle. In the Calvin cycle, three molecules of CO2 are added to three molecules of ribulose bisphosphate (RuBP), a 5-carbon sugar already present in the stroma.

-This results to a total of eighteen carbons in the cycle. As the three RuBP molecules accept a molecule of carbon dioxide, they immediately break down into six 3-carbon molecules of phosphoglyceric acid which is a hexose.

Oksanka [162]3 years ago

4 0

<span>Answer: The equation for C3 cycle (calvin cycle) is 6RuBP + 6CO2 + 18ATP + 12 NADPH >->-> 6 RuBP + C6H12O6 + 18ATP + 18Pi + 12NADP+ 6CO2 molecules are needed to synthesise for one molecule of C2H12O6</span>

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Balanced equation, $Mg+2HCl\rightarrow MgCl_{2}+H_{2}$

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According to balanced equation, 2 moles of HCl produce 1 mol of $H_{2}$ .

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So, theoretical yield of $H_{2}$ = $(0.550\times 2.016)g=1.11g$

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