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Naily [24]
3 years ago
5

Write the equation for the production of one hexose sugar molecule from carbon dioxide

Chemistry
2 answers:
Naddik [55]3 years ago
5 0

Answer;

6CO2 + 18ATP + 12 NADPH → C6H12O6 + 18ATP + 18Pi + 12NADP+

Explanation;

-The process of Calvin Cycle Synthesizes Hexoses from Carbon Dioxide and Water.

-The ATP and NADPH molecules produced by the light-dependent reactions of photosynthesis power sugar synthesis in the Calvin cycle. In the Calvin cycle, three molecules of CO2 are added to three molecules of ribulose bisphosphate (RuBP), a 5-carbon sugar already present in the stroma.

-This results to a total of eighteen carbons in the cycle.  As the three RuBP molecules accept a molecule of carbon dioxide, they immediately break down into six 3-carbon molecules of phosphoglyceric acid which is a hexose.

Oksanka [162]3 years ago
4 0
<span>Answer: The equation for C3 cycle (calvin cycle) is 6RuBP + 6CO2 + 18ATP + 12 NADPH >->-> 6 RuBP + C6H12O6 + 18ATP + 18Pi + 12NADP+ 6CO2 molecules are needed to synthesise for one molecule of C2H12O6</span>
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Answer:

66m

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3 0
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Answer:

Second order

Explanation:

We could obtain the order of reaction by looking at the table very closely.

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a situation in which the rate of reaction was tripled;

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x/0.01 = 4.19/2.10

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4 0
3 years ago
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8 0
3 years ago
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Answer:

hello your question is incomplete below is the missing part of the question

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