Write the equation for the production of one hexose sugar molecule from carbon dioxide

Chemistry

2 answers:

Naddik [55]3 years ago

5 0

Answer;

6CO2 + 18ATP + 12 NADPH → C6H12O6 + 18ATP + 18Pi + 12NADP+

Explanation;

-The process of Calvin Cycle Synthesizes Hexoses from Carbon Dioxide and Water.

-The ATP and NADPH molecules produced by the light-dependent reactions of photosynthesis power sugar synthesis in the Calvin cycle. In the Calvin cycle, three molecules of CO2 are added to three molecules of ribulose bisphosphate (RuBP), a 5-carbon sugar already present in the stroma.

-This results to a total of eighteen carbons in the cycle. As the three RuBP molecules accept a molecule of carbon dioxide, they immediately break down into six 3-carbon molecules of phosphoglyceric acid which is a hexose.

Oksanka [162]3 years ago

4 0

<span>Answer: The equation for C3 cycle (calvin cycle) is 6RuBP + 6CO2 + 18ATP + 12 NADPH >->-> 6 RuBP + C6H12O6 + 18ATP + 18Pi + 12NADP+ 6CO2 molecules are needed to synthesise for one molecule of C2H12O6</span>

You might be interested in

When dissolved in water, a neutral molecule of calcium chloride dissociates into three ions - one calcium ion and two chloride i

Mashcka [7]

Explanation:

Calcium chloride is an ionic compound as it is formed by transfer of an electron to each chlorine atom.

So, being an ionic compound calcium chloride is able to dissociate completely into water.

Hence, the dissociation reaction will be as follows.

$CaCl_{2}(s) \rightarrow Ca^{2+}(aq) + 2Cl^{-}(aq)$

Since, two electrons has been lost by single calcium atom. Therefore, calcium atom will have a charge of +2.

Thus, we can conclude that the charge on the calcium ion, in elementary units is +2.

8 0

2 years ago

Identify the solute with the highest van't Hoff factor. And how do you determine which one is highest?

german

Answer : The correct option is, (A) $AlCl_3$

Explanation :

Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.

We can determine the van't Hoff factor by the association and dissociation of the compound.

(A) $AlCl_3$

It is an electrolyte that dissociates to give aluminum ion and chloride ion.

The dissociation of $AlCl_3$ will be,

$AlCl_3\rightarrow Al^{3+}+3Cl^{-}$