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2 years ago

Please help me thanks

Mathematics

2 answers:

sergiy2304 [10]2 years ago

5 0

Vertical intercept (y) = 2
Horizontal intercept (x) = -4

Sladkaya [172]2 years ago

4 0

Answer:

i agree the person above is correct

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The mean age of 5 people in a room is 40 years. A person enters the room. The mean age is now 40. What is the age of the person

ad-work [718]

Answer:

Step-by-step explanation:

5 people in the room have 5*40 = 200 years altogether

a new person is X years old.

Now 6 people have (200 + x) years altogether.

Mean age of 6 people is (200+x)/6. and it is also = 40.

So,

(200+x)/6 = 40

200 + x = 240

x = 40

6 0

3 years ago

Find the GCF of 36 a^2 b+6ab^3

bagirrra123 [75]

I believe GCF is 36a^2b+6ab^3

8 0

3 years ago

The 3 in 75,341 is ______ the value of the 3 in 293,467

givi [52]

Answer:

3 in 75,341 = the hundreth place. 3 in 293,467 = the thousandth place.

Step-by-step explanation:

6 0

3 years ago

The vertex of this parabola is at (3,5) when the y-value is 6 the x value -1 what is the coefficient of the squared term in the

ale4655 [162]

Answer:

1/16

Step-by-step explanation:

Here,

Vertex =(3,5)

x= -1, y=6

Simply,eqn of parabola is given by ax^2+bx+c=y

So, coefficient of squared term (x^2) is 'a'

Therefore, we've to find the value of a

Moving on to solution:

a-b+c=6 ___(i) (by putting the given values of x and y in eqn of parabola )

We know that,

Vetex=(-b/2a, ( 4ac-b^2)/4a)

(3,5) = (-b/2a , (4ac-b^2)/4a)

Equating corresponding sides,we get

3= -b/2a

b=-6a___(ii)

Again,

5=(4ac-b^2)/4a

5=(4ac/4a) - (b^2/4a)

5= c- (36a^2/4a) (by putting value of b from eqn ii )

5= c-9a___(iii)

Now,moving back to the first eqn

a+6a+5+9a=6

16a=1

therefore,a=1/16

Hence ,the required value of coefficient of squared term is 1/16.

I tried my best to give clear explanation as much as I know. It's just we've have to find the value of a . For that, you can use any method you find easier.

3 0

3 years ago

A rectangles length is 2 meters greater than its width if the e perimeter is greater than 112 what is the rectangles possible wi

pishuonlain [190]

Answer:

Step-by-step explanation:

Perimeter of a rectangle = 2(L +W)

Given L = W + 2 and the perimeter is greater than 112 meters?

P rect < 2(L +W) L = W + 2

P rect < 2(W + 2 +W)

< 2(2W+2)

112 < 4W + 4 solve for W

(112 - 4)/4 < (4W +4 - 4)/4

108/4 < (4W + 0)/4

27 < W

the width has to be greater than 27 meters

5 0

3 years ago