Answer: The spontaneous intermingling of atoms among different substances is accomplished by diffusion.
Explanation:
Diffusion means to spread out. In diffusion, the molecules or atoms move from a region of high concentration to low concentration.
In other words, we can say that the spontaneous intermingling of atoms among different substances is accomplished by diffusion. Diffusion depends on the random walk of an atom or molecule.
Molecular kinetic energy is the energy of a gas at ordinary temperature in which the atoms or molecules are in rapid motion.
Displacement is the property in which a reactive element displaces less reactive element from its position.
Condensation is the process of changing water vapor into liquid.
Thus, it can be concluded that the spontaneous intermingling of atoms among different substances is accomplished by diffusion.
Answer:
21.2 gm
Explanation:
calculate the mass of butane needed to produce 64.1 g of carbon dioxide to three significant figures and appropriate units
butane is the hydrocarbon C4H10
in combustion, we react hydrocarbons with O2 to form CO2 and H2O
so
C4H10 + O2----------------> CO2 + H2O
BALANCE
2C4H10 + 1302--------> 8CO2 + 10 H2O
the molar mass of CO2 is 12 + 16X2 = 44
64.1 gm of CO2 is
64.1/44 = 1.46 MOLES OF CO2,
FOR EVERY 8 MOLES OF CO2 WE NEED 2 MOLES OF BUTANE IT IS A
8:2 OR 4:1 RATIO. THE MOLES OF C4H10 ARE 1/4 THE MOLES OF CO2
SO
THE MOLES OF C4H10 H10 ARE 1.46/4 =0.365 MOLES
THE MOLAR MASS OF BUTANE IS 58.12
0.365 MOLES OF C4H10 HAS A MASS OF 0.365 X 58.12 = 21.2 gm
Answer:
Cr₂S₃
Explanation:
From the question given above, the following data were obtained:
Mass of chromium (Cr) = 0.67 g
Mass of chromium sulfide = 1.2888 g
Empirical formula =?
Next, we shall determine the mass of sulphur (S) in the compound. This can be obtained as follow:
Mass of chromium (Cr) = 0.67 g
Mass of chromium sulfide = 1.2888 g
Mass of sulphur (S) =?
Mass of S = (Mass of chromium sulfide) – (Mass of Cr)
Mass of S = 1.2888 – 0.67
Mass of S = 0.6188 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of Cr = 0.67 g
Mass of S = 0.6188 g
Divide by their molar mass
Cr = 0.67 / 52 = 0.013
S = 0.6188 / 32 = 0.019
Divide by the smallest
Cr = 0.013 / 0.013 = 1
S = 0.019 / 0.013 = 1.46
Multiply by 2 to express in whole number
Cr = 1 × 2 = 2
S = 1.46 × 2 = 3
Therefore, the empirical formula of the compound is Cr₂S₃
Answer:
Explanation:
Hello,
In this case, by knowing that we have 1 billion (
1,000,000,000) of atoms of sulfur, via the Avogadro's number we can firstly compute the moles:
Then, by using the atomic mass of sulfur (32 g/mol), we can finally compute the mass:
Best regards.
