When a radioactive atom emits an alpha particle, the original atom's atomic number decreases by four.
1 answer:
You might be interested in
Answer:
Explanation:
Hello!
In this case, since the equation we use to model the heat exchange into the calorimeter and compute the heat of reaction is:
We plug in the mass of water, temperature change and specific heat to obtain:
Now, this enthalpy of reaction corresponds to the combustion of propyne:
Whose enthalpy change involves the enthalpies of formation of propyne, carbon dioxide and water, considering that of propyne is the target:
However, the enthalpy of reaction should be expressed in kJ per moles of C3H4, so we divide by the appropriate moles in 7.00 g of this compound:
Now, we solve for the enthalpy of formation of C3H4 as shown below:
So we plug in to obtain (enthalpies of formation of CO2 and H2O are found on NIST data base):
Best regards!
Answer:
The answer is
<h2>12,574,750.83 moles</h2>Explanation:
In order to find the moles of CO2 we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question
N = 7.57 × 10^30 molecules of CO2
We have
We have the final answer as
<h3>12,574,750.83 moles</h3>Hope this helps you