All categories

3 years ago

Which of the following is a starting compound during cellular respiration? Carbon dioxide Glucose Mitochondria Water

Chemistry

2 answers:

Flauer [41]3 years ago

7 0

Answer:

glucose is your answer

Explanation:

victus00 [196]3 years ago

4 0

Cellular respiration involves use of glucose and oxygen to generate energy inform of ATP and carbon dioxide. ATP is then used for various activities of a cell. The process takes place in the mitochondrion and oxygen acts as the electron acceptor in the electron transport chain that results to energy generation. Therefore the answer is Glucose.

You might be interested in

The following information is given for benzene, C6H6, at 1atm: boiling point = 80.1 °C Hvap(80.1 °C) = 30.7 kJ/mol specific heat

user100 [1]

Answer: The heat required for the process is 4.24 kJ

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of benzene = 24.8 g

Molar mass of benzene = 78.11 g/mol

Putting values in above equation, we get:

$\text{Moles of benzene}=\frac{24.8g}{78.11g/mol}=0.318mol$

To calculate the enthalpy change of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

$q$ = amount of heat absorbed = ?

n = number of moles = 0.318 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = 30.7 kJ/mol

Putting values in above equation, we get:

$30.7kJ/mol=\frac{q}{0.318mol}\\\\q=(30.7kJ/mol\times 0.318mol)=4.24kJ$

Hence, the heat required for the process is 4.24 kJ

6 0

3 years ago

The d-metals iron, copper, and manganese form cations with different oxidation states. For this reason, they are found in many o

choli [55]

Answer:

They have electrons in their 3d- and 4s-orbital for bond formation.

Explanation:

d- metals or transition metal are metal which form ion with partially filled d-orbital. Examples are iron and manganese.

The metals have 2 electrons in their 4s orbital. If only this is used for bonding, they will form compounds where they have oxidation State of +2 as seen in MnO.

If two 4s and one of 3d electrons are used, oxidation state of +3 is formed as seen in FeCl3.

If two 2s electron I used with two 3d electrons, compound with oxidation state of +4 is formed as seen in MnO2

4 0

3 years ago

Read 2 more answers

A 50.0 mL sample of an aqueous H2SO4 solution is titrated with a 0.375 M NaOH solution. The equivalence point is reached with 62

vesna_86 [32]

Answer: The concentration of $H_2SO_4$ is 0.234 M

Explanation:

According to the neutralization law,

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1$ = basicity $H_2SO_4$ = 2

$M_1$ = molarity of $H_2SO_4$ solution = ?

$V_1$ = volume of $H_2SO_4$ solution = 50.0 ml

$n_2$ = acidity of $NaOH$ = 1

$M_1$ = molarity of $NaOH$ solution = 0.375 M

$V_1$ = volume of $NaOH$ solution = 62.5 ml

Putting in the values we get:

$2\times M_1\times 50.0=1\times 0.375\times 62.5$

$M_1=0.234M$

Therefore concentration of $H_2SO_4$ is 0.234 M

6 0

3 years ago

Calculate the pH of a buffer solution prepared by mixing 60.0 mL of 1.00 M lactic acid and 25.0 mL of 1.00 M sodium lactate.

marshall27 [118]

This problem could be solved easily using the Henderson-Hasselbach equation used for preparing buffer solutions. The equation is written below:

pH = pKa + log[(salt/acid]

Where salt represents the molarity of salt (sodium lactate), while acid is the molarity of acid (lactic acid).

Moles of salt = 1 mol/L * 25 mL * 1 L/1000 mL = 0.025 moles salt
Moles of acid = 1 mol/L* 60 mL * 1 L/1000 mL = 0.06 moles acid
Total Volume = (25 mL + 60 mL)*(1 L/1000 mL) = 0.085 L

Molarity of salt = 0.025 mol/0.085 L = 0.29412 M
Molarity of acid = 0.06 mol/0.085 L = 0.70588 M

Thus,
pH = 3.86 + log(0.29412/0.70588)
pH = 3.48

4 0

3 years ago

The ratio of carbon atoms to hydrogen atoms to oxygen atoms in a molecule of dicyclohexyl maleate is 4 to 6 to 1. what is its mo

Semenov [28]

Knowing the ratio between atoms we can write an empirical formula:

C4H6O 

we compute the molar mass of this single formula: 
4x12 + 6 x 1 + 16 x1 = 70 g / mol 

Now, as we know the actual molar mas being 280 g/mol, we divide this number by 70 and we get the ratio between empirical formula and molecular actual formula: 

280 / 70 = 4 

This means that actual molecular formula is: 

(C4H6O)4 or 

C16H24O4

3 0

3 years ago

Read 2 more answers