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Evgesh-ka [11]
3 years ago
5

Solutions of mercury (I) nitrate and potassium bromide are mixed

Chemistry
1 answer:
Afina-wow [57]3 years ago
7 0
With that informatio you can:

1) Write the chemical equation
2) Balance the chemical equation
3) State the molar ratios
4) Predict if precipitation occurs.

I will do all four, for you:

1) Chemical equation:

mercury(I) nitrate  potassium bromide    mercury(I) bromide  potassium nitrate
<span>Hg2(NO3)2             +        KBr                   → Hg2Br2          +      KNO<span>3

2) Balanced chemical equation
</span></span>
<span>Hg2(NO3)2 + 2KBr → Hg2Br2 + 2KNO<span>3

3) Molar ratios or proportions:

1 mol </span></span><span>Hg2(NO3)2 : 2 mol KBr : 1 mol Hg2Br2 : 2 mol KNO<span>3

4) Prediction of precipitation.

You can use the solubility rules or a table of solubilities. I found in a table of solutiblities that mercury(I) bromide is insoluble and potassium bromide is soluble, Then you can predict that the precipitation of mercury(I) bromide will occur.


</span></span>
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If the concentration of Mg2+ in the solution were 0.039 M, what minimum [OH−] triggers precipitation of the Mg2+ ion? (Ksp=2.06×
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Answer:

2.30 × 10⁻⁶ M

Explanation:

Step 1: Given data

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Solubility product constant of Mg(OH)₂ (Ksp): 2.06 × 10⁻¹³

Step 2: Write the reaction for the solution of Mg(OH)₂

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Ksp = 2.06 × 10⁻¹³ = [Mg²⁺] × [OH⁻]²

[OH⁻] = 2.30 × 10⁻⁶ M

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