The mass of the ethylene glycol used is 14.26 g
<h3>What is the freezing point?</h3>
The freezing point is the temperature at which a liquid is converted to a solid.
Given that;
ΔT = 0.0°C - ( -4.3°C) = 4.3°C
ΔT = 4.3°C
But we know that
ΔT = k m i
m = ΔT/k i
m = 4.3°C/1.86 °C/m * 1
m = 2.3 m
Now;
Let the mass of ethylene glycol be m
Molar mass of ethylene glycol = 62 g/mol
Mass of solvent = 100.0 g or 0.1 Kg
Then;
2.3= m/62/0.1
2.3 = m/62 * 0.1
m = 2.3 * 62 * 0.1
m = 14.26 g
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Tying marshmallows utilising toothpicks together was difficult about building the model
Building the construct was challenging because of the toothpicks used to connect the marshmallows.
• The Salt Model consists of three layers that can be stacked on top of one another to form a NaCl unit cell.
Using the model in two different orientations is possible if the layers are connected.
• As shown by the salt model, the majority of basic inorganic compounds are composed of ions that interchange endlessly rather than discrete molecules.
Little marshmallows could serve as an analogy for the tiny sodium atoms.
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To calculate the molarity of a solution, you divide the moles of solute by the volume of the solution expressed in liters. Note that the volume is in liters of solution and not liters of solvent. When a molarity is reported, the unit is the symbol M and is read as “molar”.
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