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3 years ago

Explain how liquid can enter the gas phase without reaching its boiling point

1 answer:

ioda3 years ago

4 0

Evaporation is a phase transition from the liquid phase to the gas phase that occurs at temperatures below the boiling point at a given pressure.

hope this helps :)

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Define the SI unit fro length, mass time , and temperature

Julli [10]

Length=The distance between two points

Mass=The amount of matter contained in a body

Time=The interval or duration between two events

Temperature=The hotness and coldness of a body

7 0

3 years ago

a. Compare the motion of the particles as a solid, liquid, and gas. b. What happens to the intermolecular bonds during phase cha

natta225 [31]

The answer A I’m positively absolutely

3 0

3 years ago

PLEASE ANSWER QUICKLY !!! FOR MY CHEMISTRY CLASS !!!!!

Sergio039 [100]

The density of the unknown metal, given the data is 1.67 g/mL

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

With the above formula, we can determine the density of the unknown metal. Details below:

<h3>How to determine the density </h3>

Mass of unknown metal = 20 - 0 = 20 g
Volume of unknown metal = 12 - 0 = 12 mL
Density of unknown metal =?

Density = mass / volume

Density of unknown metal = 20 / 12

Density of unknown metal = 1.67 g/mL

Thus, the density of unknown metal is 1.67 g/mL

Learn more about density:

brainly.com/question/952755

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4 0

2 years ago

A compound, C4H6O, exhibits IR absorption at 1705 cm-1. Its carbon NMR shifts are given below. The number of hydrogens at each c

Airida [17]

Answer:

Methacrylaldehyde

Explanation:

The first step is the calculation of the IHD (index hydrogen deficiency):

$IHD=~\frac{2C+2+N-H-X}{2}$

$IHD=~\frac{2(2)+2-6}{2}=2$

This value indicates that we have 2 double bonds. Now, if we check the IR info we can conclude that we have an oxo group (C=O) due to the signal in 1705 cm^-1 . So, the options that we can have are aldehyde or ketone.

If we analyze the NMR info we have a signal in 194.7 with only 1 hydrogen. This indicates that necessary we have an aldehyde due to the hydrogen. Also, for the signal in 14 we will have a $CH_3$ , for the signal at 134.2 we will have a $CH_2$ and for the signal at 146.0 we will have a quaternary carbon (no hydrogens present).

So, we will have a $CH_3$ , $CH_2$ , C (without hydrogens), an aldehyde group and a double bond.

When we put all this together we will obtain the Methacrylaldehyde (see figure).

5 0

4 years ago

Determine the gram formula mass of the product

dimulka [17.4K]

For the whole set of problems, always remember the Avogadro’s number is 6.023*10^23 units per mole of a substance. Units could be atoms, molecules or formula units.

The first question asks for the number of molecules of NaNO3. The molar mass of NaNO3 is 85 grams per mole. So,

150g NaNO3(1mole NaNO3/85 grams NaNO3)(6.023*10^23 molecules/1mole NaNO3)=1.063*10^24 molecules of NaNO3

5.7*10^46 molecules of NaNO3(1mole NaNO3/6.023*10^23 molecules)(85 grams NaNO3/1mole NaNO3) = 8.044*10^24 grams NaNO3

For the molar mass of water, we have 18.02grams per mole.

301 moles H2O(18.02 grams H2O/1 mole H2O) = 5424.02 grams H2O

For the molar mass of sulfuric acid, we have 98.08 grams per mole.

25g H2SO4(I mole H2SO4/98.08g H2SO4) = 0.2549 mole H2SO4

For the molar mass of Ca(OH)2, we have 74.1 grams per mole.

252gCa(OH)2(1mol/74.1g)(6.023*10^23/1mol) = 2.048*10^24 molecules of Ca(OH)2

For the molar mass of calcium, we have 40 grams of Ca per mole.

6.7*10^35 atoms Ca(1 mole Ca/6.023*10^23 atoms)(40g Ca/1mol Ca) = 4.45*10^13 grams Ca

6 0

3 years ago