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Sever21 [200]
2 years ago
14

How many grams of hno3 would you need to prepare 5.5 l of this solution

Chemistry
1 answer:
k0ka [10]2 years ago
3 0

8305 grams of HNO3 would be needed to prepare 5.5L of a solution. Details on how to calculate mass is found below.

<h3>How to calculate mass?</h3>

The mass of a substance in a solution can be calculated using the following formula:

Density = mass ÷ volume

According to this question, 5.5L of a HNO3 solution is given.

Density of HNO3 is 1.51 g/cm³

Volume of HNO3 = 5500mL

1.51 = mass/5500

mass = 8305g

Therefore, 8305 grams of HNO3 would be needed to prepare 5.5L of a solution.

Learn more about mass at: brainly.com/question/19694949

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Explanation:

The Ksp of PbI₂ is:

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When 328mL of 0.00345M NaI(aq) is combined with 703mL of 0.00802M Pb(NO₃)₂. Molar concentration of I⁻ and Pb²⁺ are:

[I⁻] = 0.00345M × (328mL / (328mL+703mL) =<em> 1.098x10⁻³M</em>

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<em />

Q = [I⁻]²[Pb²⁺] <em>Concentrations not necessary in equilibrium</em>

If Q = Ksp, the solution is saturated, Q > Ksp, the solution will form a precipitate, if Q < Ksp, the solution is not saturated.

Replacing:

Q = [1.098x10⁻³M]²[5.469x10⁻³M] = 6.59x10⁻⁹

As Q < Ksp, the solution is not saturated and <em>will not form a precipitate</em>.

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