All categories

3 years ago

How do I do molarity equations?

1 answer:

8 0

To calculate the molarity of a solution, you divide the moles of solute by the volume of the solution expressed in liters. Note that the volume is in liters of solution and not liters of solvent. When a molarity is reported, the unit is the symbol M and is read as “molar”.
I hope this helped :)
Please make me the branliest! Have a good night/ good day!!

You might be interested in

Predict the following product(s) of the following reaction? F2 + KCI →

slega [8]

Answer:

${ \rm{F _{2(g)} + 2KCl _{(aq)} → { \bold{2KF _{(g)} + Cl_{2(g)} }}}}$

Explanation:

» The prediction is 98% correct because single displacement reaction type is highly possible.

This is because Fluorine has is more electronegative than Chlorine in Potassium Chloride. So, it strongly displaces Chlorine from the solution hence forming Chlorine gas.

» The 2% of wrong prediction maybe because of wrong reactant measurements following mole concept chemistry.

If you are asked the observation,

Observation » A green yellowish gas is formed.

This gas is Chlorine gas (Cl2)

5 0

2 years ago

If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr

Alinara [238K]

Answer:

The value of the heat capacity of the Calorimeter $C_c$ = 54.4 $\frac{J}{c}$

Explanation:

Given data

Heat added Q = 4.168 KJ = 4168 J

Mass of water $m_w$ = 75.40 gm

Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c

From the given condition

Q = $m_w C_w$ ΔT + $C_c$ ΔT

Put all the values in above equation we get

4168 = 75.70 × 4.18 × 11.24 + $C_c$ × 11.24

611.37 = $C_c$ × 11.24

$C_c$ = 54.4 $\frac{J}{c}$

This is the value of the heat capacity of the Calorimeter.

7 0

3 years ago

A gas at 400 k is placed in a 4.0 l moveable piston. The gas is cooled to 252 k. What is the new volume of the piston?

katrin [286]

Answer:

2.52L

Explanation:

Given parameters:

T₁ = 400K

V₁ = 4L

T₂ = 252K

unknown

V₂ = ?

Solution:

To solve this problem, we are going to apply charle's law. The law states that the volume of a fixed mass of gas is directly proportional to temperature provided pressure is constant.

Mathematically,

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

Substitute and solve for V₂

$\frac{4}{400} = \frac{V_{2} }{252}$

V₂ = 2.52L

6 0

3 years ago

Can someone please help

miskamm [114]

Answer:

Explanation:

6 0

3 years ago

Read 2 more answers

An aqueous sodium acetate, NaC2H3O2 , solution is made by dissolving 0.395 mol NaC2H3O2 in 0.505 kg of water. Calculate the mola

liq [111]

Answer: The molality of $NaC_2H_3O_2$ solution is 0.782 m

Explanation:

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molality:

$\text{Molality of solution}=\frac{\text{Moles of solute}}{\text{Mass of solvent (in kg)}}$ .....(1)

Given values:

Moles of $NaC_2H_3O_2$ = 0.395 mol

Mass of solvent (water) = 0.505 kg

Putting values in equation 1, we get:

$\text{Molality of }NaC_2H_3O_2=\frac{0.395mol}{0.505kg}\\\\\text{Molality of }NaC_2H_3O_2=0.782m$

Hence, the molality of $NaC_2H_3O_2$ solution is 0.782 m

8 0

3 years ago