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Varvara68 [4.7K]
3 years ago
6

The basic unit of capacity in SI is the A)meter. B)liter. C)kilogram.

Mathematics
1 answer:
RoseWind [281]3 years ago
5 0

Answer: a) meter

Step-by-step explanation:

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Find the slope given: (11, 12) &amp; (1,8)<br> m =
maksim [4K]
12/20 hope this help you
6 0
3 years ago
2<br>Decrease R420 in the ratio 4:7​
Oxana [17]

Step-by-step explanation:

Let the numbers are 4x and 7x. According to the question if each number is increased by 20, the ratio becomes 7 : 9.

Then,

( 4x + 20 ) : ( 7x + 20 ) = 7 : 9

9( 4x + 20 ) = 7( 7x + 20 )

9( 4x ) + 9( 20 ) = 7( 7x ) + 7( 20 )

9( 20 ) - 7( 20 ) = 7( 7x ) - 9( 4x )

2( 20 ) = 49x - 36x

40 = 13 x

40 / 13 = x

Therefore, number are :–

4 x = 4( 40 / 13 ) = 160 / 13

7 x = 7( 40 / 13 ) = 280 / 13

4 0
3 years ago
Nick was playing a game with his friends. In the game, he received points for correct answers and lost points for incorrect answ
HACTEHA [7]

Answer:

-7

Step-by-step explanation:

because 15-22= -7

he started at 0, gained 15 points but then lost 22, so after the two problems he'd have a score of -7.

3 0
3 years ago
The formula c=√(a^2+4b^2 ) Solve the equation for b. That means get “b” all by itself on one side of the equation. Show your wor
fiasKO [112]

Answer:

b^{2} =\frac{c^{2}-a^{2}  }{4}

Step-by-step explanation:

I believe this is the correct answer. In order to check that my equations are correct I put in some dummy numbers.

a= 2

b=4

c= 2\sqrt{17}

7 0
3 years ago
He takes a random sample of 49 recent charterholders and computes a mean salary of $172,000 with a standard deviation of $35,000
uysha [10]

Answer:

the 90% of confidence intervals for the average salary of a CFA charter holder

 (1,63,775 , 1,80,000)

Step-by-step explanation:

<u>Explanation</u>:-

random sample of n = 49 recent charter holders

mean of sample (x⁻) =  $172,000

standard deviation of sample( S) = $35,000

Level of significance α= 1.645

<u> 90% confidence interval</u>

(x^{-} - Z_{\alpha } \frac{s}{\sqrt{n} } , x^{-} + Z_{\alpha } \frac{s}{\sqrt{n} })

(172000 - 1.645 \frac{35000}{\sqrt{49} } , 172000 +1.645 \frac{35000}{\sqrt{49} })

on calculation , we get

(1,63,775 , 1,80,000)

The mean value lies between the 90% of confidence intervals

(1,63,775 , 1,80,000)

4 0
3 years ago
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