The sum of three consecutive odd integers is 76 less then seven times the middle number. The three integers are 17, 19 and 21 respeectively
<h3><u>Solution:</u></h3>
Since each consecutive odd integer is separated by a difference of 2
Let "n" be the first integer
n + 2 be the second integer
n + 4 be the third integer
Given that the sum of three consecutive odd integers is 76 less then seven times the middle number
Which means,
The sum of ( n, n + 2, n + 4) is equal to 76 less than seven times the middle number ( 7(n + 2))
That is,
n + n + 2 + n + 4 = 7(n + 2) - 76
3n + 6 = 7n + 14 - 76
4n = 68
n = 17
So we get:
First integer = n = 17
Second integer = n + 2 = 17 + 2 = 19
Third integer = n + 4 = 17 + 4 = 21
Thus the three consecutive odd integers are 17, 19 and 21 respeectively
Answer:
The answer is
<h2>8.6 units</h2>
Step-by-step explanation:
The distance between two points can be found by using the formula
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
(8,9) and (3,2)
The distance between them is
We have the final answer as
<h3>8.6 units to the nearest tenth</h3>
Hope this helps you
Answer:
A.10
Step-by-step explanation:
An exponent is a number or letter written above and to the right of a mathematical expression called the base.
x is the base and n is the exponent or power. Definition: If x is a positive number and n is its exponent, then xn means x is multiplied by itself n times.
Answer:
6(9r-7)
Step-by-step explanation:
54r–42
Both 54 and 43 can be divided by 6
54/6 =9 and 42/6 =7
6*9r - 6*7
Factor out the 6
6(9r-7)
