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LuckyWell [14K]
2 years ago
13

If the volume of a cone is 10 m^3 what is its height if the area of the base is 10 m^2?

Mathematics
2 answers:
Alex2 years ago
5 0

Answer:

3 m

Step-by-step explanation:

\textsf{Volume of a cone}=\sf \dfrac{1}{3}  b h \quad\textsf{(where b is the area of the circular base and h is the height)}

Given:

  • volume = 10 m³
  • Area of base = 10 m²

\implies \sf 10=\dfrac{1}{3} \cdot 10 \cdot h

\implies \sf 10=\dfrac{10}{3}h

\implies \sf 30=10h

\implies \sf h=\dfrac{30}{10}=3

Bad White [126]2 years ago
4 0

Answer:

height: 3 meter

Explanation:

\sf volume : \frac{1}{3}  \ x \ base \ area \ x \  height

Here given:

  • base area: 10 m²
  • height: h
  • volume: 10 m³

Solve:

\longrightarrow \sf 10 = \frac{1}{3} \ x  \ 10 \ x  \ h

\longrightarrow \sf 10 = \frac{10}{3} \ x   \ h

\longrightarrow \sf \frac{10 \ x  \ 3}{10}  =   h

\longrightarrow \sf 3  =   h

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Find the angle measures. Justify your responses.
MatroZZZ [7]

Answer:

m∠3 = 2x - 10° and m∠6 = 3x + 20

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Step-by-step explanation:

a ║ b

m∠2 = m∠6                     If ║ cut by a transversal, then corresponding angles

                                         are ≅ and =

m∠7 = m∠3                   If ║ cut by a transversal, then corresponding angles

                                       are ≅ and =

m∠2 = 3x + 20              Given

m∠7 = 2x - 10                 Given    

m∠6 + m∠3 = 180°         If ║ cut by a transversal, then each pair of same-side

                                       interior angles (also called consecutive interior angles

                                       are supplementary (sum = 180°) .    

3x + 20 + 2x - 10 = 180°

5x + 10 = 180°

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x = 34°

Answer:   m∠3 = 2x - 10° and m∠6 = 3x + 20

                m∠3 = 2(34) - 10  ;    m∠6 = 3(34) + 20

                 m∠3 = 58°          ;    m ∠6 = 122°

                                 

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Answer:

176

Step-by-step explanation:

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62/141

400 x 62/141 = 175.8

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Answer:

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