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Sauron [17]
2 years ago
10

In the following exercises, write the first five terms of the sequence whose general term is given.

Mathematics
1 answer:
Sladkaya [172]2 years ago
4 0

Answer:

2, 9 , 16 , 23 , 30 ......

Step-by-step explanation:

a_n = 7n - 5

       a_1 = 7*1 - 5  = 7-5 = 2\\\\a_2 = 7*2 - 5 = 14 - 5 = 9\\\\a_3 = 7*3 - 5 = 21 - 5 = 16\\\\a_4= 7*4 - 5 = 28 - 5 = 23\\\\a_5= 7*5 - 5 = 35 - 5 = 30

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What is the (10) for?
miv72 [106K]

Answer:

2(10) is implied multiplication

Step-by-step explanation:

( 18+2) + 2(10) ÷4 -2

PEMDAS

Parentheses first

( 20) + 2(10) ÷4 -2

Then exponents ( we have none)

Then multiply and divide from left to right

20 + 20÷4 -2

20 + 5-2

Then add and subtract from left to right

25 -2

23

2(10) is implied multiplication

4 0
3 years ago
Read 2 more answers
A church rings its bells every 15 minutes, the school rings its bells every 20 minutes and the day care center rings its bells e
ankoles [38]

Answer:

As few as just over 345 minutes (23×15) or as many as just under 375 minutes (25×15).

Imagine a simpler problem: the bell has rung just two times since Ms. Johnson went into her office. How long has Ms. Johnson been in her office? It could be almost as short as just 15 minutes (1×15), if Ms. Johnson went into her office just before the bell rang the first time, and the bell has just rung again for the second time.

Or it could be almost as long as 45 minutes (3×15), if Ms. Johnson went into her office just after the bells rang, and then 15 minutes later the bells rang for the first time, and then 15 minutes after that the bells rang for the second time, and now it’s been 15 minutes after that.

So if the bells have run two times since Ms. Johnson went into her office, she could have been there between 15 minutes and 45 minutes. The same logic applies to the case where the bells have rung 24 times—it could have been any duration between 345 and 375 minutes since the moment we started paying attention to the bells!

Step-by-step explanation:

7 0
3 years ago
Evaluate 4a-3b when a=5 and b=-2
den301095 [7]
4a - 3b

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26 is your answer. 
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3 years ago
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Answer:

B. move forward 7, left 6, and down 5

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By the <u>convention of 3D geometr</u>y, the coordinates of a point (x,y,z) represent how far the point is from the origin forward-backward , right/left , up-down respectively with prior one for the positive coordinate and latter for the negative coordinate.

so we need to move forward 7 for x=7 then to left 6 for y=-6 and then down 5 for z=-5.

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